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3 years ago

The Baldwin family walked of a mile in of an hour. What is their unit rate in miles per hour? (5 points)

1 answer:

3 0

So walked 4/5 mile in a 4/9 h so just use the rule of 3 simple

60 minutes ------ 1 hour
x min. ----------- 4/9 h
--------------------------------
x = 4/9 *60/1 = 240/9 = 26,6 min.

4/5 mile -------in 26,6 min.
1 mile -------- x min.
-----------------------------
x = 1*26,6/(4/5) = 26,6 /(0,8) = 33,25 min.

1 mile ..... 33,25 min.
x miles ----- 60 min.
---------------------------
x = 60/33,25 = 1,8 miles

so their unit rate in miles per hour will be 1,8 miles / hour

hope this will help you.

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Hailey is a high school basketball player. In a particular game, she made some three point shots and some free throws (worth one

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Answer: the system of equations are

3x + y = 14

y = 4x

Step-by-step explanation:

Let x represent the number of three point shots that Hailey made.

Let y represent the number of free throws(worth one point each) that Hailey made.

Hailey made some three point shots and some free throws and

scored a total of 14 points. This would be expressed as

3x + y = 14

Hailey made 4 times as many free throws as three point shots. This would be expressed as

y = 4x

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3 years ago

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Zanzabum

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2 years ago

Find the domain of <br> - y/(y-6) +15/(y+6)<br> - y-10/y^2+3

ArbitrLikvidat [17]

Answer:

Step-by-step explanation:

Domain of a function represents the set of x-values (input values) and y-values (output values) of the function represent the Range of the function.

Given function is,

If Domain (input values) of this function is,

{-12, -6, 3, 15}

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2 years ago

In a certain region, about 6% of a city's population moves to the surrounding suburbs each year, and about 4% of the suburban po

Sedbober [7]

Answer:

City @ 2017 = 8,920,800

Suburbs @ 2017 = 1, 897, 200

Step-by-step explanation:

Solution:

- Let p_c be the population in the city ( in a given year ) and p_s is the population in the suburbs ( in a given year ) . The first sentence tell us that populations p_c' and p_s' for next year would be:

0.94*p_c + 0.04*p_s = p_c'

0.06*p_c + 0.96*p_s = p_s'

- Assuming 6% moved while remaining 94% remained settled at the time of migrations.

- The matrix representation is as follows:

$\left[\begin{array}{cc}0.94&0.04\\0.06&0.96\end{array}\right] \left[\begin{array}{c}p_c\\p_s\end{array}\right] = \left[\begin{array}{c}p_c'\\p_s'\end{array}\right]$

- In the sequence for where x_k denotes population of kth year and x_k+1 denotes population of x_k+1 year. We have:

$\left[\begin{array}{cc}0.94&0.04\\0.06&0.96\end{array}\right] x_k = x_k_+_1$

- Let x_o be the populations defined given as 10,000,000 and 800,000 respectively for city and suburbs. We will have a population x_1 as a vector for year 2016 as follows:

$\left[\begin{array}{cc}0.94&0.04\\0.06&0.96\end{array}\right] x_o = x_1$

- To get the population in year 2017 we will multiply the migration matrix to the population vector x_1 in 2016 to obtain x_2.

$x_2 = \left[\begin{array}{cc}0.94&0.04\\0.06&0.96\end{array}\right]\left[\begin{array}{cc}0.94&0.04\\0.06&0.96\end{array}\right] x_o$

- Where,

$x_o = \left[\begin{array}{c}10,000,000\\800,000\end{array}\right]$

- The population in 2017 x_2 would be:

$x_2 = \left[\begin{array}{cc}0.94&0.04\\0.06&0.96\end{array}\right]\left[\begin{array}{cc}0.94&0.04\\0.06&0.96\end{array}\right] \left[\begin{array}{c}10,000,000\\800,000\end{array}\right] \\\\\\x_2 = \left[\begin{array}{c}8,920,800\\1,879,200\end{array}\right]$

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3 years ago