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Alona [7]
3 years ago
5

The Baldwin family walked of a mile in of an hour. What is their unit rate in miles per hour? (5 points)

Mathematics
1 answer:
Lisa [10]3 years ago
3 0
So walked 4/5 mile in a 4/9 h  so just use the rule of 3 simple 

60 minutes ------ 1 hour
x min. ----------- 4/9 h
--------------------------------
x = 4/9 *60/1 = 240/9 =  26,6 min. 

4/5 mile -------in 26,6 min.
1 mile --------   x min.
-----------------------------
x = 1*26,6/(4/5) = 26,6 /(0,8) = 33,25 min. 

1 mile ..... 33,25 min.
x miles ----- 60 min.
---------------------------
 x = 60/33,25 = 1,8 miles 

so their unit rate in miles per hour will be 1,8 miles / hour 

hope this will help you.
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The circumference of a circle exceeds the radius by 74 cm. Find the radius of the circle.​
saw5 [17]

Answer:

14 cm.

Step-by-step explanation:

Let the radius of the circle = r cm.

Then circumference of circle = 2 π r.

Since circumference exceeds the radius by 74 cm

Therefore, according to the question,

\sf \:2 π r = r+ 74

\sf \: =   > 2 \times  \frac{22}{7}  \times r =  r \:  + 74

\sf \: =  >  \frac{44r}{7}  -r  = 74

\sf \:  =  > \frac{44r - 7r}{7}  = 74

\sf \: =  >  \frac{37r}{7}  = 74

\sf \: =  > r =  \frac{7 \times 74}{37}

\sf \: =  >  r = 14

  • Hence, the radius of the circle is 14 cm.

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3 0
2 years ago
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The volume of this prism is 4375cm3.<br> The area of the cross-section is 125cm2.<br> Work out x
fomenos

Answer:

x is 35 cm

Step-by-step explanation:

To find the value of x, we will divide the volume by the cross-section

Mathematically, that will be;

4375/125 = 35 cm

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2 years ago
Samantha works at a nursery where she pots plants. It takes her 112 hours to pot 12 plants. Question 1 Part A How many plants ca
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DanielleElmas [232]

Answer:

Step-by-step explanation:

Given expression is,

\text{cot}A=\frac{1}{2}(\text{cot}\frac{A}{2}-\text{tan}\frac{A}{2})

To prove this identity we will take the right side of the identity,

\frac{1}{2}(\text{cot}\frac{A}{2}-\text{tan}\frac{A}{2})=\frac{1}{2}(\frac{1}{\text{tan}\frac{A}{2}}-tan\frac{A}{2})

                         =\frac{1}{2}(\frac{1-\text{tan}^2\frac{A}{2}}{tan\frac{A}{2}})

                         =\frac{1}{2}[\frac{2(1-\text{tan}^2\frac{A}{2})}{2tan\frac{A}{2}}]

                         =\frac{1}{2}(\frac{2}{\text{tan}A} ) [Since \text{tan}A=\frac{2\text{tan}\frac{A}{2}}{1-\text{tan}^2\frac{A}{2}}]

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Answer:

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Just rearrange the equation.

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