By the quadratic formula, the <em>solution</em> set of the <em>quadratic</em> equation is formed by two <em>real</em> roots: x₁ = 0 and x₂ = - 12.
<h3>How to find the solution of quadratic equation</h3>
Herein we have a <em>quadratic</em> equation of the form a · m² + b · m + c = 0, whose solution set can be determined by the <em>quadratic</em> formula:
x = - [b / (2 · a)] ± [1 / (2 · a)] · √(b² - 4 · a · c) (1)
If we know that a = - 1, b = 12 and c = 0, then the solution set of the quadratic equation is:
x = - [12 / [2 · (- 1)]] ± [1 / [2 · (- 1)]] · √[12² - 4 · (- 1) · 0]
x = - 6 ± (1 / 2) · 12
x = - 6 ± 6
Then, by the quadratic formula, the <em>solution</em> set of the <em>quadratic</em> equation is formed by two <em>real</em> roots: x₁ = 0 and x₂ = - 12.
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Answer:
Step-by-step explanation:
To determine the area of the logo you have to calculate the area of the triangle and the square that comform it and then add the four areas.
Area of the square.
To calculate the area of the square you have to calculate the square of one of its sides, following the formula:
Where "a" is the length of one of its side.
The side length of the square is a=7cm, so its area will be:
Area of the triangles.
The three triangles are equal, they have a base equal to the side of the square, i.e. with a length of 7cm, and their height is h=4cm.
To calculate the area of one triangle, you have to multiply its base by its height and divide by 2, following the formula:
The area calculated the correspond to one triangle, since all triangles are congruent, you have to multiply the said area by 3 to determine the area of three figures:
Now that the area of all shape are calculated, you have to add them to determine the area of the logo:
Answer:
Answer is 3bu2(DeEZ)=1
Step-by-step explanation:
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<span>the correct equation is
- 4j² + 3j - 28 =0
ax² + bx + c,
a = -4, b=3 c =- 28.
The discriminent D = b² - 4.a.cD = 3² - 4(-4)(-28)D = -439
If D ≥ 0 there are either 2 roots or one double if = 0)if D< 0, there are no real roots (but 2 imaginary roots)Since D < 0, then there is no real roots
The answer there is no real roots</span>
