Download connects Q&A they have the answers on there
Data:
<span>Number of shares: 500
name of fund
nav offer price
hat mid-cap $18.94 $19.14
Profit $6,250.
1) Investment = number of shares * offer price = <em />500 * $ 19.14 = $ 9570
2) Total net value = profit + investment = $6250 + $9570 = $15820
3) NAV = total net value / number of shares = $15820 / 500 = $31.64
Answer: option c: 31.64
</span>
For this case we must write in algebraic symbology the expression described above:
We have an equation, then:
- x squared plus y squared:
- minus 2x plus 7y plus 1:
- equals zero:
We construct the equation:
Answer:
Basically, what this asks you is to maximize the are A=ab where a and b are the sides of the recatangular area (b is the long side opposite to the river, a is the short side that also is the common fence of both corrals). Your maximization is constrained by the length of the fence, so you have to maximize subject to 3a+b=450 (drawing a sketch helps - again, b is the longer side opposite to the river, a are the three smaller parts restricting the corrals)
3a+b = 450
b = 450 - 3a
so the maximization max(ab) becomes
max(a(450-3a)=max(450a-3a^2)
Since this is in one variable, we can just take the derivative and set it equal to zero:
450-6a=0
6a=450
a=75
Plugging back into b=450-3a yields
b=450-3*75
b=450-225
b=215
Hope that helps!
Answer:
A
Step-by-step explanation:
Its A the other ones don't make sense
