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3 years ago

If the angles is 180 and there is 3 parts (3x+94) and (x+36) and (2x-4) what is x

Mathematics

1 answer:

DiKsa [7]3 years ago

3 0

Hehe, I thought I'd get this one wrong, but x=10. Remember, that a straight angle must add up to 180 degrees. So I added all the angles; (3x+94)+(x+36)+(2x-4)=180. I took away the parentheses having 3x+94+x+36+2x-4=180. Remember from Algebra 1, to simplify terms, we add the polynomials. 94+36-4=126. 3x+x+2x= 6x. Our simplified equation is 120+6x=180. Now we can answer. 180-120=60. 60=6x. So therefore, for all x, x equals 10.

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Mrs. Robinson, an insurance agent, earns a salary of $4,800 per year plus a 3% commission on her sales. The average price of a p

nekit [7.7K]

Answer:

Required inequality is $4800+183x>8000$ .

Step-by-step explanation:

Given that Mrs. Robinson, an insurance agent, earns a salary of $4,800 per year plus a 3% commission on her sales. The average price of a policy she sells is $6,100. Write an inequality to find how many policies Mrs. Robinson must sell to make an annual income of at least $8,000.

Calculation is given by:

Salary per year = $4,800

Average price of a policy = $6,100.

commission on her sales = 3%

Then commission on $6,100 = 3% of $6,100 = 0.03 ($6,100) = $183

Let number of policies Mrs. Robinson must sell to make an annual income of at least $8,000 = x

then total commission on x policies = 183x

Total income using x policies = 4800+183x

Since she wants to make an annual income of at least $8,000. so we can write inequality as:

$4800+183x>8000$

Hence required inequality is $4800+183x>8000$ .

5 0

3 years ago

Sarah is a computer engineer and manager and works for a software company. She receives a

daser333 [38]

Answer:

a) Number of projects in the first year = 90

b) Earnings in the twelfth year = $116500

Total money earned in 12 years = $969000

Step-by-step explanation:

Given that:

Number of projects done in fourth year = 129

Number of projects done in tenth year = 207

There is a fixed increase every year.

a) To find:

Number of projects done in the first year.

This problem is nothing but a case of arithmetic progression.

Let the first term i.e. number of projects done in first year = $a$

Given that:

$a_4=129\\a_{10}=207$

Formula for $n^{th}$ term of an Arithmetic Progression is given as:

$a_n=a+(n-1)d$

Where $d$ will represent the number of projects increased every year.

and $n$ is the year number.

$a_4=129=a+(4-1)d \\\Rightarrow 129=a+3d .....(1)\\a_{10}=207=a+(10-1)d \\\Rightarrow 207=a+9d .....(2)$

Subtracting (2) from (1):

$78 = 6d\\\Rightarrow d =13$

By equation (1):

$129 =a+3\times 13\\\Rightarrow a =129-39\\\Rightarrow a =90$

Number of projects in the first year = 90

b)

Number of projects in the twelfth year =

$a_{12} = a+11d\\\Rightarrow a_{12} = 90+11\times 13 =233$

Each project pays $500

Earnings in the twelfth year = 233 $\times$ 500 = $116500

Sum of an AP is given as:

$S_n=\dfrac{n}{2}(2a+(n-1)d)\\\Rightarrow S_{12}=\dfrac{12}{2}(2\times 90+(12-1)\times 13)\\\Rightarrow S_{12}=6\times 323\\\Rightarrow S_{12}=1938$

It gives us the total number of projects done in 12 years = 1938

Total money earned in 12 years = 500 $\times$ 1938 = $969000

8 0

2 years ago

Find x. I need the answer asap, please.

Nezavi [6.7K]

Answer:

x=28

Step-by-step explanation:

x+24+100+x=180

x+124+x=180

2x+124=180

2x=180-124

2x=56

divide both side by number attached to the x

therefore x=28

6 0

2 years ago

D(1) = 1. d(n) = n.d(n-1), for n > 2

melamori03 [73]

Answer:

Step-by-step explanation:

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2 years ago

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Describe the roots of the polynomial function shown below.

Allisa [31]

Answer:

Graphically. As shown below, the roots of a polynomial are the values of x that make the polynomial zero, so they are where the graph crosses the x-axis, since this is where the y value (the result of the polynomial) is zero. The roots are the two green dots.

Step-by-step explanation:

8 0

3 years ago

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