Answer:
C = M0(M1+M2+M3)+M1(M2+M3)+M2M3 is the equation which suits
Explanation:
From the given data we can state that we need to activate only one product i.e 1------>activated 0-------->means inactivated and also only one slot is activated at a time.The resultant will be no data inputs n control bits and 2 to the power n output bits.
Umm okay...
The density of water is 1.0 g/cm^3
Which will float in water
A.) Ice (Density = 0.92 g/cm^3) Float or sink
B.) Wood (Density = 0.45 g/cm^3) Float or sink
C.) Bone (Density = 1.7 g/cm^3) Float or sink
If you help answer this it will be much appreciated thank you
The options are missing from the question,below are the options to choose from;
A) incorrect (or missing) routes in a routers routing table
B) incorrect DNS configuration on the PC
C) incorrect default gateway configuration on the PC
D) duplicate IP addresses on your LAN
Answer: The correct answer to the question is option A
INCORRECT (OR MISSING) ROUTES IN A ROUTERS ROUTING TABLE.
Explanation: When it is possible for a PC to ping some devices but not actually all,we can then make an assumption that either it has a wrong subnet that is configured or the router from the path to the remote device actually has an incorrect or a missing routes to the device.
Answer:
The code will be a java-script code
Explanation:
public abstract class Phone{
private String phoneNumber ;
public Phone (String thePhoneNumber) {
phoneNumber = thePhoneNumber ;
}
public String getPhoneNumber ( ) {
return phoneNumber ;
}
public String toString ( ) {
phoneNumber = "# (" + phoneNumber + ") " ;
return phoneNumber ;
}
public abstract boolean createConnection (Network status) ;
public abstract void closeConnection( ) ;
}
Answer:
dog
Explanation:
Given the code :
>>> A = [21, 'dog', 'red']
>>> B = [35, 'cat', 'blue')
>>> C = [12, 'fish', 'green']
>>> E = [A, B, C]
the value of E[0][1]
Here, square boxes is used to select the value at E[0] ; the output is then used to select the value at index 1 of E[0] output.
Note that, indexing starts at 0; hence first list element is 0, then, 1, 2, and so on.
At
E[0] ; list E, index 0 (first element in the list) , gives an output A
Then, A[1] ; list A, index 1 (second element in the list) gives 'dog'
