Answer:
Keeping you hands on the homerow keys
Explanation:
Answer:
<em>Given Data:</em>
<em>myBytes BYTE 10h, 20h, 30h, 40h </em>
<em>myWords WORD 3 DUP(?), 2000h </em>
<em>myString BYTE "ABCDE"</em>
<em />
Based on the data that we are given we can conclude that:
(a). a. EAX = 1
b. EAX = 4
c. EAX = 4
d. EAX = 2
e. EAX = 4
f. EAX = 8
g. EAX = 5
did you just put random a*s word together and expect us to know the ¨answer¨
Answer:
3,265,920 unique ID exist.
Explanation:
The nine digits are from 0 to 9, there are ten bits from 0 -9,
0, 1, 2, 3, 4, 5, 6, 7, 8, 9
The first is select from the highest bit (9), and the second is selected at random from 0 - 9, the third bit to the last must be unique and different from each other;
number of unique IDs = 9 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2
Multiplying the nine bits of unique IDs = 3,265,920.
