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marishachu [46]
3 years ago
14

Two different factories both produce a certain automobile part. The probability that a component from the first factory is defec

tive is 2%, and the probability that a component from the second factory is defective is 5%. In a supply of 180 of the parts, 100 were obtained from the first factory and 80 from the second factory.
a. What is the probability that a part chosen at random from the 180 is from the first factory?
b. What is the probability that a part chosen at random from the 180 is from the second factory?
c. What is the probability that a part chosen at random from the 180 is defective?
d. If the chosen part is defective, what is the probability that it came from the first factory?
Mathematics
1 answer:
Ulleksa [173]3 years ago
5 0

Answer:

a. 55.56%

b. 44.44%

c. 3.33%

d. 33.33%

Step-by-step explanation:

total supply =  180

a. In the first factory the total number obtained = 100

probability that the chosen part is from the first

= 100/180

= 0.5556

= 55.56%

b. In the second factory total = 80

probability that the chosen part is from the second

= 80/180

= 0.4444

= 44.44%

c. probability that part chosen at random from 180 is defective

= 2% * 0.5556 + 5% * 0.4444

= 0.02*0.5556 + 0.05*0.4444

=  0.011112 + 0.0222

= 0.03331

= 3.33%

d. probability it came rom the first factory if it is defective

\frac{0.02*0.5556}{0.02*0.5556+0.05*0.4444}

= \frac{0.011112}{0.011112+0.0222}

= \frac{0.011112}{0.033312}

= 0.33357

= 33.33%

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Use the Euclidean algorithm to express 1 as a linear combination of x and n.

a. 52^{-1}\equiv40\pmod{77} because

77 = 1*52 + 25

52 = 2*25 + 2

25 = 12*2 + 1

so we can write

1 = 25 - 12*2 = 25*25 - 12*52 = (77 - 52)(77 - 52) - 12*52 = 77^2 - 2*52*77 + 52^2 - 12*52

Taken modulo 77 leaves us with

1\equiv52\cdot52-12\cdot52\equiv40\cdot52\pmod{77}\implies52^{-1}\equiv40\pmod{77}

b. First, 77\equiv25\pmod{52}, so really we're looking for the inverse of 25 mod 52. We've basically done the work in part (a) already:

1 = 25*25 - 12*52

Taken modulo 52, we're left with

1\equiv25\cdot25\pmod{52}\implies25^{-1}\equiv25\pmod{52}

c. The EA gives

71 = 1*53 + 18

53 = 2*18 + 17

18 = 1*17 + 1

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3 years ago
If $4,000 is invested in an account for 25 years. Calculate the total interest earned at the end of 25 years if the interest is:
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The interest is a) $7000

b) $17709.73

c) $18672.62

d) $18901.67

What is the formula for simple and compound interest?

Simple interest = (P× r× t)

Compound interest = P(1+r/n)^nt - P

We will find the interest as shown below:

P=$4,000

t=25 years

a) r=7%=0.07

Simple interest = (P× r× t)

= (4000×0.07×25)

= $7000

b) r=7%=0.07

Compound interest = P(1+r)^t - P

= 4000(1+0.07)^25-4000

= $17709.73056

rounding to nearest cents

= $17709.73

c) r=7%=0.07

n=4

Compound interest = P(1+r/n)^nt - P

= 4000(1+0.07/4)^(25*4)-4000

= $18672.62375

rounding to nearest cent

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c) $18672.62

d) $18901.67

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