the total mass in kilograms y of the cinder block and brick is 
.
<u>Step-by-step explanation:</u>
Here we have , A kilogram is equal to approximately 2.2 pounds. A cinder block weighs x pounds. A brick has a mass of 0.6 kilogram. We need to find What is the total mass in kilograms y of the cinder block and brick . Let's find out :
According to given data in question ,
⇒ 
⇒ 
A cinder block weighs x pounds and a brick has a mass of 0.6 kilogram . Let total mass in kg of the cinder block and brick is y , i.e.
⇒ 
⇒ 
⇒
Therefore , the total mass in kilograms y of the cinder block and brick is .
Answer:
13 or B
Step-by-step explanation:
1 pound=16 oz
4 1/4=4.25, 4.25*16=68
68+10=78
78/6=13
<span>Postulates are helpful because it helps you plan and solve geometry problems.
That's my guess. It doesn't tell me in the text either.</span>
Answer:
0.5 m/s
Falling at 32 feet/s
Step-by-step explanation:
For the first question, since it only asks for the average time between 2 and 8 seconds, those are the only two important values. When taking the inputs and outputs for 2 and 8 seconds after the throw ((2,3) and (8,6) respectively), we can take the average change by finding the change in y/change in x, so we have (6-3)/(8-2)=0.5 meters/second.
For the second question, we can similarly just take the values from the initial drop (144) and after two seconds (80) to get that the rate of change is (144-80)/(-2)=-32, so it's falling at 32 feet/second.
Let me know if you have any questions!
