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andriy [413]
3 years ago
12

When you buy an item on which sales tax is charged,the total cost is calculated by the formula T=P+s/100p where T is the total c

ost,p is the items price,and s is the sales tax rate (as a percent). If you pay $14.77 for an item priced at $14, what was the tax rate ?
Mathematics
1 answer:
Gennadij [26K]3 years ago
7 0

Given:

The formula for total cost is

T=p+\dfrac{s}{100}p

where, p is the price of item and s is the sales tax rate (as a percent).

You pay $14.77 for an item priced at $14.

To find:

The the tax rate.

Solution:

You pay $14.77 for an item priced at $14. So,

Total cost (T) = $14.77

Price of item (p) = $14

Putting T=14.77 and p=14 in given formula, we get

14.77=14+\dfrac{s}{100}(14)

14.77-14=\dfrac{s}{100}(14)

0.77=\dfrac{s}{100}(14)

Multiply both sides by 100.

77=14s

Divide both sides by 14.

\dfrac{77}{14}=s

5.5=s

Therefore, the tax rate is 5.5%.

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A worker was paid a salary of $10,500 in 1985. Each year, a salary increase of 6% of the previous year's salary was awarded. How
Mazyrski [523]
Note that 6% converted to a decimal number is 6/100=0.06. Also note that 6% of a certain quantity x is 0.06x.

Here is how much the worker earned each year:


In the year 1985 the worker earned <span>$10,500. 

</span>In the year 1986 the worker earned $10,500 + 0.06($10,500). Factorizing $10,500, we can write this sum as:

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In the year 1987 the worker earned

$10,500(1+0.06) + 0.06[$10,500(1+0.06)].

Now we can factorize $10,500(1+0.06) and write the earnings as:

$10,500(1+0.06) [1+0.06]=$10,500(1.06)^2.


Similarly we can check that in the year 1987 the worker earned $10,500(1.06)^3, which makes the pattern clear. 


We can count that from the year 1985 to 1987 we had 2+1 salaries, so from 1985 to 2010 there are 2010-1985+1=26 salaries. This means that the total paid salaries are:

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Factorizing, we have

=10,500[1+1.06+(1.06)^2+(1.06)^3+...+(1.06)^{26}]=10,500\cdot[1+1.06+(1.06)^2+(1.06)^3+...+(1.06)^{26}]

We recognize the sum as the geometric sum with first term 1 and common ratio 1.06, applying the formula

\sum_{i=1}^{n} a_i= a(\frac{1-r^n}{1-r}) (where a is the first term and r is the common ratio) we have:

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The answer we found is very close to D. The difference can be explained by the accuracy of the values used in calculation, most important, in calculating (1.06)^{26}.


Answer: D



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