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3 years ago

Please help ...............

Mathematics

1 answer:

Alina [70]3 years ago

3 0

Answer:

Step-by-step explanation:

(look at the picture)

We have opposite and adjacent. Therefore we must use the tangent:

$\tangent=\dfrac{opposite}{adjacent}$

$adjacent=500\\opposite=x\\\tan10^o\approx0.1763$

Substitute:

$\dfrac{x}{500}\approx0.1763$ <em>multiply both sides by 500</em>

$x\approx88.15\to x\approx88.2$

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PLEASE HELP asap :):)

Serggg [28]

Answer:C

Step-by-step explanation:

24/6=4

P6R2/ P2Q2R6

Cancel you have P4 left on top

Cancel you have R4 left on bottom

Q2 stays at bottom

4 0

3 years ago

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Please help me please!!

AysviL [449]

Answer:

198 degrees

Step-by-step explanation:

3 0

3 years ago

I know you’re supposed to change the bounds and break up the integral, but for some reason, I can’t get the 44/3. Can someone ex

tatyana61 [14]

First, look for the zeroes of the integrand in the interval [0, 6] :

x² - 6x + 8 = (x - 4) (x - 2) = 0 ⇒ x = 2 and x = 4

Next, split up [0, 6] into sub-intervals starting at the zeroes we found. Then check the sign of x² - 6x + 8 for some test points in each sub-interval.

• For x in (0, 2), take x = 1. Then

x² - 6x + 8 = 1² - 6•1 + 8 = 3 > 0

so x² - 6x + 8 > 0 over this sub-interval.

• For x in (2, 4), take x = 3. Then

x² - 6x + 8 = 3² - 6•3 + 8 = -1 < 0

so x² - 6x + 8 < 0 over this sub-interval.

• For x in (4, 6), take x = 5. Then

x² - 6x + 8 = 5² - 6•5 + 8 = 3 > 0

so x² - 6x + 8 > 0 over this sub-interval.

Next, recall the definition of absolute value:

$|x| = \begin{cases}x & \text{for }x \ge0 \\ -x & \text{for }x < 0\end{cases}$

Then from our previous analysis, this definition tells us that

$|x^2 - 6x + 8| = \begin{cases}x^2 - 6x + 8 & \text{for }0$

So, in the integral, we have

$\displaystyle \int_0^6 |x^2-6x+8| \, dx = \left\{\int_0^2 - \int_2^4 + \int_4^6\right\} (x^2 - 6x + 8) \, dx$

Then

$\displaystyle \int_0^2 (x^2 - 6x + 8) \, dx = \left(\frac13 x^3 - 3x^2 + 8x\right) \bigg|_0^2 = \frac{20}3 - 0 = \frac{20}3$

$\displaystyle \int_2^4 (x^2 - 6x + 8) \, dx = \left(\frac13 x^3 - 3x^2 + 8x\right) \bigg|_2^4 = \frac{16}3 - \frac{20}3 = -\frac43$

$\displaystyle \int_4^6 (x^2 - 6x + 8) \, dx = \left(\frac13 x^3 - 3x^2 + 8x\right) \bigg|_4^6 = 12 - \frac{16}3 = \frac{20}3$

and the overall integral would be

20/3 - (-4/3) + 20/3 = 44/3

3 0

3 years ago

Let ????=−5y????+5x????. Use the tangential vector form of Green's Theorem to compute the circulation integral ∫????????⋅???????

denpristay [2]

The value of the required integral is 50π where C is the positively oriented circle x2+y2=25

We are given a vector F = -yi + xj. A vector is a quantity with magnitude and direction that is commonly represented by a directed line segment, with length representing magnitude and orientation in space representing direction. We need to use the tangential vector form of Green's Theorem to compute the circulation integral ∫CF⋅dr where C is the positively oriented circle x² + y² = 25

Let the value of the integral be represented by the variable "I".

I = ∫∫[(/x)(x) - (/y)(-y)]dA

I = ∫∫[(1 - (-1)]dA

I = ∫∫2dA

I = 2∫∫dA

I = 2×(Area of the circle)

I = 2*(πr²)

I = 2*(π*25)

I = 50π

Hence, the value of the required integral is 50π.

To learn more about integrals, visit :

brainly.com/question/18125359

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6 0

1 year ago

In the diagram, r || s. what is the value of x?

N76 [4]

Answer:

24.8

Step-by-step explanation:

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3 years ago

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