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kogti [31]
3 years ago
8

Help with the question please​

Mathematics
1 answer:
galina1969 [7]3 years ago
5 0

Step-by-step explanation:

since all 4 sides are equal in length, the figure is a square.

let the length of the square be lm.

529 = l x l

l = 23m

perimeter = 23 x 4 = 92m

Topic: mensuration

If you like to venture further, do check out my insta (learntionary) where I regularly post useful math tips! Thank you!

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You roll a six sided die what is the probability of rolling a 4 or an odd number
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Answer:

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Gnesinka [82]

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Find the perimeter of the figure to the nearest hundredth.
babunello [35]

Answer:

50.28 inches

Step-by-step explanation:

From the Image, we can find the length of the arc of the semi-circle by dividing the circumference of the resulting circle by 2

Radius= 9in

C= 2πr

C=2*3.142*9

C=2*3.142*9

C= 56.556 inches

Hence the length of the arc is

=56.556/2

=28.278 inches

The perimeter of the shape

=28.278+5+12+5

=50.28 inches

8 0
3 years ago
How do you solve 1-5+1×(4×4-31)×8
Alja [10]
Hey there!

In order to solve this, remember PEMDAS. First, start with solving whatever is in parentheses. Then, move on to exponents. Then, complete the multiplication and division. Lastly, add or subtract anything remaining. Omit any steps that aren't present. 

Parentheses: 

<span>1 – 5 + 1 × (4 × 4 – 31) × 8
</span>1 – 5 + 1 × (–15) × 8

Multiplication/Division (Left to Right):

1 – 5 + (–15) × 8
1 – 5 + (–120)
1 – 5 – 120

Addition/Subtraction (Left to Right):

–4 – 120
–124

Your answer is –124. 

Hope this helped you out! :-)
5 0
3 years ago
The time taken to assemble a laptop computer in a certain plant is a random variable having a normal distribution of 20 hours an
ludmilkaskok [199]

Answer:

a) 40.13% probability that a laptop computer can be assembled at this plant in a period of time of less than 19.5 hours.

b) 34.13% probability that a laptop computer can be assembled at this plant in a period of time between 20 hours and 22 hours.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

\mu = 20, \sigma = 2

a)Less than 19.5 hours?

This is the pvalue of Z when X = 19.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{19.5 - 20}{2}

Z = -0.25

Z = -0.25 has a pvalue of 0.4013.

40.13% probability that a laptop computer can be assembled at this plant in a period of time of less than 19.5 hours.

b)Between 20 hours and 22 hours?

This is the pvalue of Z when X = 22 subtracted by the pvalue of Z when X = 20. So

X = 22

Z = \frac{X - \mu}{\sigma}

Z = \frac{22 - 20}{2}

Z = 1

Z = 1 has a pvalue of 0.8413

X = 20

Z = \frac{X - \mu}{\sigma}

Z = \frac{20 - 20}{2}

Z = 0

Z = 0 has a pvalue of 0.5

0.8413 - 0.5 = 0.3413

34.13% probability that a laptop computer can be assembled at this plant in a period of time between 20 hours and 22 hours.

4 0
3 years ago
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