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dedylja [7]
3 years ago
15

Please helpppp me pleaseee

Mathematics
1 answer:
Sergeu [11.5K]3 years ago
8 0
The answer is square
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4 - t = 3(t-1) - 5<br> A 3<br> B 6<br> C no solution<br> D Identity
Ket [755]

Answer:

A

Step-by-step explanation:

Given

4 - t = 3(t - 1) - 5 ← distribute and simplify right side

4 - t = 3t - 3 - 5

4 - t = 3t - 8 ( subtract 3t from both sides )

4 - 4t = - 8 ( subtract 4 from both sides )

- 4t = - 12 ( divide both sides by - 4 )

t = 3

7 0
3 years ago
Is for over two and 20/6 proportions
ad-work [718]
No they're not proportional, and it's four*.
4/2 = 2
20/6 = 3.333333333334 or 3 1/3
4 0
3 years ago
Read 2 more answers
Standard covert 3x-24 = 1 ​
larisa86 [58]

Answer:

the answer is -9 it think

6 0
2 years ago
Students in a zoology class took a final exam. They took equivalent forms of the exam at monthly intervals thereafter. After t​
juin [17]

Answer:

a. 73; b. 48.9; c. 2; d. 33.8; e. 73

Step-by-step explanation:

Assume the function was

S(t)= 73 - 15 ln(t + 1), t  ≥ 0

a. Average score at t = 0

S(0) = 73 - 15 ln(0 + 1) = 73 - 15 ln(1) = 73 - 15(0) =73 - 0 = 73

b. Average score at t = 4

S(4) = 73 - 15 ln(4 + 1) = 73 - 15 ln(5) = 73 - 15(1.61) =73 - 24.14 = 48.9

c. Average score at t =24

S(24) = 73 - 15 ln(24 + 1) = 73 - 15 ln(25) = 73 - 15(3.22) =73 - 48.28 = 24.7

d. Percent of answers retained

At t = 0. the students retained 73 % of the answers.

At t = 24, they retained 24.7 % of the answers.

\text{Percent retention} = \dfrac{\text{24.7}}{\text{73}} \times 100 \, \% = \text{33.8 \%}\\\\\text{The students retained $\large \boxed{\mathbf{33.8 \, \%}}$ of their original knowledge after two years.}

e. Maximum of the function

The maximum of the function is at t= 0.

Max = 73 %

The graph below shows your knowledge decay curve. Knowledge decays rapidly at first but slows as time goes on.

 

6 0
3 years ago
Please help!!!!
Svet_ta [14]
5 would be the best answer choice
3 0
4 years ago
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