Please help w/ this thx

Mathematics

2 answers:

andrew-mc [135]3 years ago

7 0

The answer is a , 28 square ft.

Likurg_2 [28]3 years ago

7 0

Answer:

A 28 sq feet

Step-by-step explanation:

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A string is cut into two pieces in the ratio 2 : 7. The difference between the lengths of the two pieces is 90cm. Find the lengt

Nataly_w [17]

Answer:the length of the shorter string= 36cm

Step-by-step explanation:

Let us assume the lengths are 2x and 7x since thery are in the ratio of 2 :7

Such that Length of the shorter string = 2x

and the longer string = 7x so that the difference in Length which is 90cm can be expressed as

7x- 2x= 90

5x= 90

x 90/5

x= 18

shorter string = 2 x = 2x 18= 36cm

Longer strring = 7x 18=126cm

5 0

3 years ago

Find the measure of the missing angle .

Nana76 [90]

Answer:

c = 99 and b = 81

7 0

2 years ago

Find the number b such that the line y = b divides the region bounded by the curves y = 36x2 and y = 25 into two regions with eq

Gemiola [76]

Answer:

b = 15.75

Step-by-step explanation:

Lets find the interception points of the curves

36 x² = 25

x² = 25/36 = 0.69444

|x| = √(25/36) = 5/6

thus the interception points are 5/6 and -5/6. By evaluating in 0, we can conclude that the curve y=25 is above the other curve and b should be between 0 and 25 (note that 0 is the smallest value of 36 x²).

The area of the bounded region is given by the integral

$\int\limits^{5/6}_{-5/6} {(25-36 \, x^2)} \, dx = (25x - 12 \, x^3)\, |_{x=-5/6}^{x=5/6} = 25*5/6 - 12*(5/6)^3 - (25*(-5/6) - 12*(-5/6)^3) = 250/9$

The whole region has an area of 250/9. We need b such as the area of the region below the curve y =b and above y=36x^2 is 125/9. The region would be bounded by the points z and -z, for certain z (this is for the symmetry). Also for the symmetry, this region can be splitted into 2 regions with equal area: between -z and 0, and between 0 and z. The area between 0 and z should be 125/18. Note that 36 z² = b, then z = √b/6.

$125/18 = \int\limits^{\sqrt{b}/6}_0 {(b - 36 \, x^2)} \, dx = (bx - 12 \, x^3)\, |_{x = 0}^{x=\sqrt{b}/6} = b^{1.5}/6 - b^{1.5}/18 = b^{1.5}/9$