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2 years ago

14

Help PLEASE ill give brainliest!

2 answers:

Serhud [2]2 years ago

7 0

Answer:

EDIT: Ah, the screenshot changed, but I'll answer anyways!

The answer is 8 cents, or .08. Simply, we divide 5.60 by 70 to get this answer!

I hope this helps!

kupik [55]2 years ago

6 0

Answer:1.49

Step-by-step explanation:sorry if im wrong

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How would you write apples grow on trees in conditional statements?

MariettaO [177]

If it is an apple, then it grows on trees.

4 0

3 years ago

Find the volume of a cylinder with a diameter of 8 inches and a height that is 3 times the radius. Use 3.14 for pi round answer

masha68 [24]

Answer:

603.19

Step-by-step explanation:

v=π $r^{2} h$

pi is 3.14

Radius= Diameter/2= 4, so r square= 16

Height= Radius*3=12

So volume= 3.14*16*12=603.19

6 0

2 years ago

What is the value of x in the equation 3x -1/9<br> y = 18, when y = 27?<br> 5<br> 7<br> 45 63

almond37 [142]

Answer:

$x=7$

Step-by-step explanation:

we have

$3x-\frac{1}{9}y=18$

Substitute the value of y=27 in the equation and find the value of x

so

$3x-\frac{1}{9}(27)=18$

$3x-3=18$

$3x=18+3$

$3x=21$

$x=7$

4 0

2 years ago

Find 3rd and 5th form by using nth term formula tn=a+(n-1)d when tn=a+(n-1)d when a=2 and d=3.

lawyer [7]

Answer:

t3 = 8, t5 = 14

Step-by-step explanation:

t3 = 2 + (3-1) × 3

t3 = 2 + (2) × 3

t3 = 2 + 6

t3 = 8

t5 = 2 + (5-1) × 3

t5 = 2 + (4) × 3

t5 = 2 + 12

t5 = 14

8 0

2 years ago

I know you want to answer this question.

Alik [6]

Answer:

D. x = 3

Step-by-step explanation:

$\frac{1}{2} ^{x-4}$ - 3 = $4^{x-3}$ - 2

First, convert $4^{x-3}$ to base 2:

$4^{x-3}$ = $(2^{2})^{x-3}$

$\frac{1}{2} ^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Next, convert $\frac{1}{2} ^{x-4}$ to base 2:

$\frac{1}{2} ^{x-4}$ = $(2^{-1})^{x-4}$

$(2^{-1})^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{-1})^{x-4}$ = $2^{-1*(x-4)}$

$2^{-1*(x-4)}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{2})^{x-3}$ = $2^{2(x-3)}$

$2^{-1*(x-4)}$ - 3 = $2^{2(x-3)}$ - 2

Apply exponent rule: $a^{b+c}$ = $a^{b}$ $a^{c}$ :

$2^{-1(x-4)}$ = $2^{-1x}$ * $2^{4}$ , $2^{2(x-3)}$ = $2^{2x}$ * $2^{-6}$

$2^{-1 * x}$ * $2^{4}$ - 3 = $2^{2x}$ * $2^{-6}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$2^{-1x}$ = $(2^{x})^{-1}$ , $2^{2x}$ = $(2^{x})^{2}$

$(2^{x})^{-1}$ * $2^{4}$ - 3 = $(2^{x})^{2}$ * $2^{-6}$ - 2

Rewrite the equation with $2^{x} = u$ :

$(u)^{-1}$ * $2^{4}$ - 3 = $(u)^{2}$ * $2^{-6}$ - 2

Solve $u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2:

$u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2

Refine:

$\frac{16}{u}$ - 3 = $\frac{1}{64}$ $u^{2}$ - 2

Add 3 to both sides:

$\frac{16}{u}$ - 3 + 3 = $\frac{1}{64}$ $u^{2}$ - 2 + 3

Simplify:

$\frac{16}{u}$ = $\frac{1}{64}$ $u^{2}$ + 1

Multiply by the Least Common Multiplier (64u):

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify:

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify $\frac{16}{u}$ * 64u:

1024

Simplify $\frac{1}{64}$ $u^{2}$ * 64u:

$u^{3}$

Substitute:

1024 = $u^{3}$ + 64u

Solve for u:

u = 8

Substitute back u = $2^{x}$ :

8 = $2^{x}$

Solve for x:

x = 3

4 0

3 years ago