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pychu [463]
3 years ago
7

Twice a number (z) added to 21 is equal to 9 times the number added to 7. What is the number?

Mathematics
1 answer:
pickupchik [31]3 years ago
5 0

Answer:

The number is  2

Step-by-step explanation:

Twice a number (z) = 2*z = 2z

Twice a number (z) added to 21  = 2z + 21

9 times the number added to 7 = 9z + 7

9z + 7 = 2z + 21

Subtract 2z form both sides

9z - 2z + 7 = 21

       7z + 7 = 21

Subtract 7 from both sides

7z = 21 - 7

 7z = 14

Divide both sides by 7

z = 14/7

z = 2

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2 years ago
10 3/9- 10 2/5 Im to lazy to do it please help me out.
coldgirl [10]

Answer:

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Step-by-step explanation:

10 3/9 - 10 2/5

we need to convert mixed fractions to improper fractions

10 \frac{3}{9}  =  \frac{10 \times 9 + 3}{9}  =  \frac{93}{9}

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Now, we have 93/9 - 52/5

We need to equate the denominators, before subtracting them.

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8 0
2 years ago
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Step-by-step explanation:

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3 years ago
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Answer:

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3 years ago
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