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pogonyaev
3 years ago
8

Monique rolls a six-sided number cube labeled 1 to 6.

Mathematics
2 answers:
ycow [4]3 years ago
7 0
P(rolling a 4) is 1/6
geniusboy [140]3 years ago
3 0
1/6 or ≈ 16.67%

the odds of rolling any one number are 1/6
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What is the domain and range of 4n/n-5 -2?
nlexa [21]

Answer:

Domain: (-∞, 5)∪ (5, ∞)

Range: (-∞, 2)∪ (2, ∞)

7 0
3 years ago
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In a right triangle whose area is 12, each leg is as long as the side of a certain square. What is the area of the square?
kakasveta [241]
The area of a Square is 144 because 12x12 is 144 and if both sides are 12 then that equals 144. 

Hope this helps!
4 0
3 years ago
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Perform the computation:
adoni [48]

9514 1404 393

Answer:

  √42 ≈ 6.48074

Step-by-step explanation:

Put the values in place of the corresponding variables and do the arithmetic.

  \sqrt{(a)(b)}=\sqrt{(14)(3)}=\boxed{\sqrt{42}\approx6.48074}

_____

42 = 2·3·7 is not a perfect square, nor does it have any perfect square factors. Its square root is irrational.

7 0
3 years ago
Which equation justifies why nine to the one third power equals the cube root of nine?
AVprozaik [17]

Answer:

nine to the one third power all raised to the third power equals nine raised to the one third times three power equals nine

Step-by-step explanation:

we know that

The <u><em>Power of a Power Property</em></u> , states that :To find a power of a power, multiply the exponents

so

(a^{b})^{c}=a^{b*c}

In this problem we have

9^{\frac{1}{3}} =\sqrt[3]{9}

Remember that

\sqrt[3]{9}=9^{\frac{1}{3}}

Raise to the third power

[9^{\frac{1}{3}}]^3

Applying the power of power property

9^{\frac{3}{3}}

9^{1}

9

therefore

nine to the one third power all raised to the third power equals nine raised to the one third times three power equals nine

8 0
3 years ago
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pam deposited $6,900 in a savings account with simple interest. Four months later she had earned $23 in interest. What was the i
3241004551 [841]

Answer:

1%

Step-by-step explanation:

We use the simple interest equation of A=P(1+rt).

A-the total amount with interest earned

P-the initial amount or principal

r-rate

t-time in years

We substitute the values P=6900, A=6923, and t=0.33 since 4 months divided by 12 months is 0.333 years. We then solve for r.

6923=6900(1+r(0.33))\\6923=6900(1+0.33r)\\\frac{6923}{6900} =\frac{6900(1+0.33r)}{6900} \\1.0033=1+0.33r\\1.0033-1=1-1+0.33r\\0.0033=0.33r

Our final step is to divide both sides by 0.33.

\frac{0.0033}{0.33} =\frac{0.33r}{0.33} \\0.01=r

This is the decimal of the rate. We convert to a percentage by multiplying by 100. 0.01(100)=1%.


5 0
3 years ago
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