1/4 + 1/2 + x = −3/4
get a common denominator 1/4
1/4 +2/4 +x = -3/4
combine like terms
3/4 +x =-3/4
subtract 3/4 from each side
x = -3/4 -3/4
x = -6/4
divide top and bottom by 2
x = -3/2
x = -1 1/2
Answer : x = -1 1/2
Answer:
You would start with 00.-6 and stop a-5954
Step-by-step explanation:
Usando las relaciones entre velocidad, distancia y tiempo, se encuentra que ella condujo a una velocidad media de 90,5 km/h.
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La <u>velocidad </u><u>es la distancia dividida por el tiempo</u>, por lo que:

- Total de 135,75 km, o sea,

- Llego en 1,5 horas, o sea,

La velocidad es:

División de decimales, o sea, seguimos multiplicando los números por 10 hasta que ninguno sea decimal:

Ella condujo a una velocidad media de 90,5 km/h.
Un problema similar es dado en brainly.com/question/24558377
Answers:
- x = 10
- angle CAT = 126 degrees
- angle MUD = 54 degrees
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Explanation:
∠CAT and ∠MUD are supplementary, which means the angle measures add to 180. They form a straight line.
( m∠CAT ) + ( m∠MUD ) = 180
( 11x+16 ) + ( 4x+14 ) = 180
11x+16 + 4x+14 = 180
(11x+4x) + (16+14) = 180
15x+30 = 180
15x = 180-30
15x = 150
x = 150/15
x = 10
Let's find each angle based on this x value
- m∠CAT=11x+16 = 11*10+16 = 110+16 = 126 degrees
- m∠MUD=4x+14 = 4*10+14 = 40+14 = 54 degrees
Those two angles add to 126+54 = 180 to confirm we do indeed have supplementary angles, and confirm the correct answers.