Answer:
t_a = 7 s
t_w = 5 s
Step-by-step explanation:
Given:
- The average speed in air v_a = 16 m/s
- The average speed in water v_w = 3 m/s
- The total distance D = 127 m
- The total time T = 12 s
Find:
How long did the stone fall in air and how long did it fall in the water?
Solution:
- Lets time taken by stone to drop through air as t_a = t_a.
- The time taken in water would be t_w = (12 - t_a)
- The total distance covered can be calculated as:
D = v_a*t_a+ v_w*(12 - t_a)
127 = 16*t_a + 3*(12 - t_a)
Simplify and solve for t:
91 = 16*t_a - 3t_a
13*t_a = 91
t_a = 7 s
t_w = 5 s
Answer:
No
Step-by-step explanation:
the radius squared is 49 times π, which is roughly 3 means the area of the base is roughly 150 ft².
This means that one third of the height cannot be more than 100 / 150 = 2/3 of a foot. That makes the height about 2 ft, much less than the reported 25 ft.
I would answer but I’m in 6th grade and I don’t know how to
Answer: y=5x/2 - 2.5
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(-2.5-2.5)/(0-2)
m=-5/(-2)
m=5/2
y=mx+b
y=5x/2 + b
-2.5=5(0)/2 + b
-2.5=0 + b
b=-2.5
y=5x/2 - 2.5
