Answer:
7 
Step-by-step explanation:
In order to solve an equation like this, you'll need to find a common denominator for your Fraction.
7
+ 
7
+ 
7 
First move the terms to get
6m-m=13+2
Then collect the like terms and calculate the sum, 5m=15
Divide both sides by 5
And you get m=3
The correct answer is like terms. Hope this helps.
A) (1, 7) Doesn't
B) (0, 4) Doesn't
C) (2, –2) Doesn't
D) (3, –5) DOES
All the steps are right at the exception of line 7 (and onwards)
line 6 : 6x = 42 (it's right). Now divide both sides by 6:
line 7 should be: 6x/6 = 42/6
line 8 should be: x = 7.
Answer:
We reject H₀
we accept Hₐ seeds in the packet would germinate smaller than 93%
Step-by-step explanation:
Test of proportions
One tail-test (left side)
93 % = 0.93
p₀ = 0,93
1.- Hypothesis
<h3>
H₀ ⇒ null hypothesis p₀ = 0.93</h3><h3>
Hₐ ⇒ Alternative hypothesis p = 0.875</h3><h3>
2.-Confidence interval 95 %</h3><h3>
α = 0,05 </h3><h3>
and </h3><h3>
z(c) = - 1.64</h3><h3>
3.- Compute z(s)</h3><h3>
z(s) = (p - p₀)/√(p₀*q₀)/n z(s) = (0.875-0.93)/√0.93*0.07)200</h3><h3>
z(s) = - 0,055/ √0.0003255</h3><h3>
z(s) = - 0.055/ 0.018</h3><h3>
z(s) = - 3,06</h3><h3>
4.-Compere z(c) and z(s)</h3><h3>
z(s) < z(c) -3.06 < -1.64</h3><h3>
z(s) is in rejection region, we reject H₀</h3>