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kumpel [21]
4 years ago
11

What set of transformations could be applied to rectangle ABCD to create A'B'C'D'? Reflected over the x-axis and reflected over

the y-axis Reflected over the y-axis and rotated 180° Reflected over the x-axis and rotated 90° counterclockwise Reflected over the y-axis and rotated 90° counterclockwise

Mathematics
1 answer:
noname [10]4 years ago
4 0
<u>Answer</u>
<span>Reflected over the x-axis and reflected over the y-axis.

<u>Explanation.</u>
When the rectangle ABCD is reflected along the x-axis, the images of ABCD will be A''(-4,-2), B''(-4,-1), C''(-1,-1) and D''(-1,-2). 
When the rectangle A'', B'', C'' and D'' is reflected on the y-axis, it will exactly map on to A'B'C'D'. 

So, the correct answer from the choices is "</span><span>Reflected over the x-axis and reflected over the y-axis". </span><span> 
</span>
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Which expressions are equivalent to 2 to the 11 power
STatiana [176]

\text{Hey there!}

\text{Which expressions are equivalent to}\bf{ \ 2^{11}}?

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\bf{2\times2=4}\\\bf{2\times2=4}\\\bf{2\times2=4}\\\bf{2\times2=4}\\\bf{2\times2\times2 = 8}\\\bf{4\times4\times4\times4=16\times16=256}\\\bf{256\times8=2,048}\\\\\boxed{\boxed{\bf{Your\ answer: 2,048}}}\checkmark

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3 years ago
Warm up:Area.how many square units will it take to fill up this rectangle?
astra-53 [7]

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Step-by-step explanation:

<em>here's</em><em> your</em><em> solution</em>

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<em>=</em><em>></em><em> </em><em>area </em><em>4</em><em>*</em><em>3</em><em> </em><em>=</em><em> </em><em>1</em><em>2</em><em>.</em><em>s</em><em>q</em><em>u</em><em>n</em><em>i</em><em>t</em>

<em>=</em><em>></em><em> </em><em>area </em><em>of </em><em>square</em><em> </em><em>=</em><em> </em><em>side^</em><em>2</em><em> </em>

<em>=</em><em>></em><em> </em><em>area </em><em>=</em><em> </em><em>1</em><em>.</em><em>s</em><em>q</em><em>u</em><em>n</em><em>i</em><em>t</em>

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5 0
3 years ago
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alexandr1967 [171]
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A triangle angles add up to 180
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cos(72) = 11/H
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answer E .



8 0
4 years ago
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Nady [450]

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=======================================================

Explanation:

Start with the equation u = e^{2x}+10

Apply the derivative and multiply both sides by 7 like so

u = e^{2x}+10\\\\\frac{du}{dx} = 2e^{2x}\\\\7\frac{du}{dx} = 7*2e^{2x}\\\\7\frac{du}{dx} = 14e^{2x}\\\\7du = 14e^{2x}dx\\\\

The "multiply both sides by 7" operation was done to turn the 2e^(2x) into 14e^(2x)

This way we can do the following substitutions:

\displaystyle \int \frac{14e^{2x}}{e^{2x}+10}dx\\\\\\\displaystyle \int \frac{1}{e^{2x}+10}14e^{2x}dx\\\\\\\displaystyle \int \frac{1}{u}7du\\\\\\\displaystyle 7\int \frac{1}{u}du\\\\\\

Integrating leads to

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Be sure to replace 'u' with e^(2x)+10 since it's likely your teacher wants a function in terms of x. Also, do not forget to have the plus C at the end. This is a common mistake many students forget to do.

To verify the answer, you can apply the derivative to it and you should get back to the original integrand of \frac{14e^{2x}}{e^{2x}+10}

4 0
2 years ago
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Aleonysh [2.5K]

Answer:

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Step-by-step explanation:

9(3y-5)=27y-45

6 0
3 years ago
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