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Bingel [31]
3 years ago
5

NEED HELP ASAP PLEASE HELP

Mathematics
2 answers:
morpeh [17]3 years ago
6 0
From point A to C, which is the length of the entire line, it's 3x + 1.
AB = 2x + 4
BC = 10

This means that AB + BC = AC

All you have to do is plug in the equations.

(2x + 4) + (10) = (3x + 1)
2x + 14 = 3x + 1
2x + 13 = 3x
13 = x

Now plug in the value of x (13) into the AC equation (3x + 1).
AC = 3(13) + 1
AC = 39 + 1
AC = 40

The answer is:
a. 40
sleet_krkn [62]3 years ago
3 0
The correct answer to your question is... a. 40
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Answer:

A≈61.94

Just plug it into a calculator

     

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Input is also called? <br>Dependent Variable<br>Independent Variable​
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independent variable input

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Put these in order starting from the smallest<br> 6^2 3^4 2^9<br> 5^3
Levart [38]

Answer:

6^2, 3^4, 5^3, and 2^9

Step-by-step explanation:

6^2= 36

3^4= 81

5^3= 125

2^9= 512

4 0
3 years ago
From experience, it is known that on average 10% of welds performed by a particular welder are defective. if this welder is requ
bulgar [2K]
Binomial distribution can be used because the situation satisfies all the following conditions:1. Number of trials is known and remains constant (n)2. Each trial is Bernoulli (i.e. exactly two possible outcomes) (success/failure)3. Probability is known and remains constant throughout the trials (p)4. All trials are random and independent of the othersThe number of successes, x, is then given byP(x)=C(n,x)p^x(1-p)^{n-x}whereC(n,x)=\frac{n!}{x!(n-x)!}
Here we're given
p=0.10  [ success = defective ]
n=3

(a) x=0
P(x)=C(n,x)p^x(1-p)^{n-x}
=C(3,0)0.1^0(1-0.1)^{3-0}
=1(1)(0.729)
=0.729

(b) x=2
P(x)=C(n,x)p^x(1-p)^{n-x}
=C(3,2)0.1^2(1-0.1)^{3-2}
=3(0.01)(0.9)
=0.027

(c) x &ge; 2
P(x)=\sum_{x=2}^3C(n,x)p^x(1-p)^{n-x}
=P(2)+P(3)
=C(n,2)p^2(1-p)^{n-2}+C(n,3)p^3(1-p)^{n-3}
=C(3,2)0.1^2(1-0.1)^{3-2}+C(3,3)0.1^3(1-0.1)^{3-3}
=3(0.01)(0.9)+1(0.001)1
=0.027+0.001
=0.028


8 0
3 years ago
Check picture if u kno geometry
Scorpion4ik [409]

Answer:

141.5 in

Step-by-step explanation

AB // CD // EF

12 / 15 = 21 / y        (By the property of 3 parallel lines and its transversals)

y = (15*21) / 12 = 26.25

CD // EF // GH

21 / y = x / 10       21 / 26.25 = x / 10

x = (21*10) / 26.25

x = 8

perimeter of ABHG = (y-14) +15 + y + 10 + (5x-3) + x + 21 + 12 = 141.5

                               

4 0
2 years ago
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