Calculate the probability that both bids are successful
Answer:
The probability that both contracs are successful is 0.21
Step-by-step explanation:
Given
E1 = the event that the bid on the first contract is successful
E2 = the event that the bid on the second contract is successful
P(E1) = 0.3
P(E2) = 0.7
Let P(A) represent the event that both contracts are successful
P(A) = P(E1 and E2)
Since both events are independent. P(A) becomes
P(A) = = P(E1 * P(E2)
By substituton
P(A) = 0.3 * 0.7
P(A) = 0.21
Hence the probability that both contracs are successful is 0.21
I believe the answer is 19.2 because you would have to do paythag. = a^2+b^2=c2 in this case it would be 7^2 + 10^2 = c
From there you would get the answer of 149, and you would have to square root it. When you square root 149 you get 12.2
12.2 + 7 = 19.2
You would add them together because you want to know the height before it broke.
7/5 x 7/1 = 49/5 or 9 4/5
Answer:
c I just saw ur question sorry if I too late
It will be
(4,000) divided by (the value of 4 in the number you left out).