2 years ago

Help me pls I really need this thank you soo much :)

Mathematics

2 answers:

horrorfan [7]2 years ago

5 0

A is the answer for number 6

Svetach [21]2 years ago

5 0

Just do 63/-9 which is -7

You might be interested in

In which quadrant is the ordered pair ( 7, -8 ) located? *

Paul [167]

Answer:

i think IV

Step-by-step explanation:

because of the picture

4 0

2 years ago

Read 2 more answers

What percent of 55 is 34

djyliett [7]

answer

.618 18 repeats

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

HELP ME SOLVE THIS PROBLEM PLEASE! :)

lukranit [14]

The answer would be the first option :
4/3r (3x)^3.

Hope this helps !

Photon

3 0

3 years ago

Read 2 more answers

What is the slope of a line that is perpendicular to the line whose equation is 8y−5x=11?

ElenaW [278]

9514 1404 393

Answer:

-8/5

Step-by-step explanation:

When you solve for y, the slope of the line is the x-coefficient. For the given line, that is ...

8y = 5x +11 . . . . . add 5x

y = 5/8x +11/8 . . . . divide by 8

The given line has a slope of 5/8. The perpendicular line will have a slope that is the opposite of the reciprocal of this:

-1/(5/8) = -8/5 . . . . slope of perpendicular line

4 0

2 years ago

Read 2 more answers

In a class of 50 students, everyone has either a pierced nose or a pierced ear. The professor asks everyone with a pierced nose

Tems11 [23]

Answer: 3

Step-by-step explanation:

Let E be the event of that student pierces ear and N be the event of that student pierces nose.

Given: $n(E\cup N=50)$

$n(E)=46\\\\n(N)=7$

For any two event A and B, we have

$n(A\cup B)=n(A)+n(B)-n(A\cap B)$

Similarly , $n(E\cup N)=n(E)+n(N)-n(E\cap N)$

$50=46+7-n(E\cap N)\\\\\Rightarrow\ n(E\cap N)=53-50=3$

Hence, 3 students have piercings both on their ears and their noses.

7 0

2 years ago