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OLEGan [10]
3 years ago
9

Find the greatest common factor of 48^a 38a

Mathematics
1 answer:
Mekhanik [1.2K]3 years ago
6 0
48^{a} and 38a GCF=1
48a and 38a GCF=2a
hope this helps
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-4.5x-2y=-12.5 3.25x-y=-0.75<br> solve by elimination
creativ13 [48]
-4.5x-2y=-12.5 and 3.25x-y=-0.75
we first multiply the second equation by -2
(-2)*(3.25x-y=-0.75)=-6.5x+2y=-1.5
add the equation to eliminate the y
so yo get (-4.5x-6.5x)=(-12.5-1.5)
-11x=-11
x=1
now we plug in x into any equation to solve for y
-45x-2y=-12.5 and x=1
(-45*1)-2y=-12.5
-4.5-2y=-12.5
-2y=-12.5+4.5
-2y=-8
y=4
then your answer is x=1 and y=4
5 0
3 years ago
There are 130 people in a sport centre. 73 people use the gym. 62 people use the swimming pool. 58 people use the track. 22 peop
Delvig [45]

Answer:

\frac{11}{87}

Step-by-step explanation:

Total number of people = 130

Number of people who use the gym = 73

Number of people who use the pool = 62

Number of people who use the track = 58

Number of people who use the gym and the pool = 22

Number of people who use the pool and the track = 29

Number of people who use the gym and the track = 25

Number of people who use all three facilities = 11

Total number of people who use at least two facilities = 22 + 29 + 25 + 11 = 87

The probability that the randomly selected person uses all three facilities = number of those who use all three facilities ÷ total number of people who use at least two facilities.

==> 11 ÷ 87

==> \frac{11}{87}

3 0
3 years ago
Evaluate the expression when x=3 , y=−4 , and z=−6.<br> z−2x/y
hichkok12 [17]

Answer:

9/2

distribute the value of x,y, and z, on the given questions, and then you do multiplication, next addition, lastly lowest term.

6 0
3 years ago
What is the median of the data?<br>30,29,16,11,16,20,21,12,13,15,15,23,30​
tia_tia [17]

Answer:

16

Step-by-step explanation:

ascending order:11,12,13,15,15,16,16,20,21,23,29,30,30

number of terms =13

median=[(n+1)/2] th term

=[(13+1)/2] th term

=[14/2] th tem

=7th term

=16

7 0
3 years ago
Are the triangles named below congruent? Justify your answer.<br> AABC<br> AAED
Anni [7]
Yes, sides AC and AD are congruent and lines BC and DE are also congruent. They also share angle A and bc of the SSA congruence Theorem that means they are congruent.
4 0
3 years ago
Read 2 more answers
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