F(x)=x^3-9x
and
g(x)=x^2-2x-3
so you just need to divide f(x) by g(x)
Therefore:
f(x)/g(x) = (x^3-9x) / (x^2-2x-3)
and of course you need to factor these two function to see if some factor would cancel another
x^3-9x = x(x^2-9)=x(x-3)(x+3)
and
x^2-2x-3 = (x-3)(x+1)
Its A.........................................
Answer:
that equation isn't factorable
Nono no well I like songs
Step-by-step explanation:lol
If she has 32 miles to the gallon, and 20 dollars, then 5*32 gives you your final answer, which is 160.
