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Paladinen [302]
3 years ago
6

What is (7-3b)(7+3b)

Mathematics
1 answer:
lidiya [134]3 years ago
8 0
The answer i got was 49-9b^2
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In a semiconductor manufacturing process, three wafers from a lot are tested. Each wafer is classified as pass or fail. Assume t
Angelina_Jolie [31]

Answer:

P(X = 0) = 0.027

P(X = 1) = 0.189

P(X = 2) = 0.441

P(X = 3)= 0.343

Step-by-step explanation:

The probability mass function P(X = x) is the probability that X happens x times.

When n trials happen, for each x \leq n, the probability mass function is given by:

P(X = x) = pe_{n,x}.p^{x}.(1-p)^{n-x}

In which p is the probability that the event happens.

pe_{n,x}, is the permutation of n elements with x repetitions(when there are multiple events happening(like one passes and two not passing)). It can be calculated by the following formula:

pe_{n,x} = \frac{n!}{x!}

The sum of all P(X=x) must be 1.

In this problem

We have 3 trials, so n = 3

The probability that a wafer pass a test is 0.7, so p = 0.7

Determine the probability mass function of the number of wafers from a lot that pass the test.

P(X = 0) = (0.7)^{0}.(0.3)^{3} = 0.027

P(X = 1) = pe_{3,1}.(0.7).(0.3)^{2} = 0.189

P(X = 2) = pe_{3,2}.(0.7)^{2}.(0.3) = 0.441

P(X = 3) = (0.7)^{3} = 0.343

5 0
3 years ago
Convert -√3-i to polar form.
Jlenok [28]

Answer:

-sqrt(3) -i = 2 cis (7pi/6)

Step-by-step explanation:

-sqrt(3) -i

We can find the radius

r = sqrt( (-sqrt(3)) ^2 + (-1) ^2)

  = sqrt( 3 + 1)

  = sqrt(4)

  = 2

theta = arctan (y/x)

          arctan (-1/-sqrt(3))

         arctan (1/sqrt(3))

theta = pi/6

But this is in the first quadrant, and we need it in the third quadrant

Add pi to move it to the third quadrant

theta = pi/6 + 6pi/6

         =7pi/6


-sqrt(3) -i = 2 cis (7pi/6)

6 0
3 years ago
Read 2 more answers
Find all integers $n$ for which $\frac{n^2+n+1}{n-1}$ is an integer.
Grace [21]
\dfrac{n^2+n+1}{n-1}=\dfrac{(n-1)^2+3(n-1)+3}{n-1}=n-2+\dfrac3{n-1}

The remainder term \dfrac3{n-1} will never vanish, and will always be rational as long as the denominator is not 1, 3, or -3.

n-1=1\implies n=2
n-1=3\implies n=4
n-1=-3\implies n=-2
7 0
3 years ago
Write down, in details the outcomes of Ordinary Differential Equations and Special<br> Functions
Anastaziya [24]

Answer:

an equation that involves some ordinary derivatives (as opposed to partial derivatives

5 0
3 years ago
Solve For X 1 &lt; x + 3 &lt; 4
EleoNora [17]

Answer:

− 2 < x < 1

Step-by-step explanation:

3 0
3 years ago
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