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marusya05 [52]
3 years ago
15

a particle moves along the x-axis so that anytime t comma measured in seconds it's position is given by...​

Mathematics
1 answer:
Natali5045456 [20]3 years ago
7 0

Given the position function <em>s(t)</em>, you can get the acceleration function by differentiating <em>s</em> twice:

velocity = <em>s'(t)</em> = -5 sin(<em>t </em>) + 3 cos(3<em>t</em> )

acceleration = <em>s''(t)</em> = -5 cos(<em>t</em> ) - 9 sin(3<em>t</em> )

Then when <em>t</em> = <em>π</em>, the particle's acceleration is

<em>s''(π)</em> = -5 cos(<em>π</em>) - 9 sin(3<em>π</em>)

… = -5 • (-1) - 9 • 0 = 5

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WARRIOR [948]

Answer:

The first one. L (t) = 0.37t + 39.67

Step-by-step explanation:

The "0.37t" is about 0.37 years of life expectancy added for each year that passes the "+ 39.67" is the starting life expectancy that has to be added to whatever the rising trend may be. just multiply 0.37 by 20  and youl have the rising trend.

6 0
3 years ago
A factory made 100 jars of peanut butter. 30% of the jars contained creamy peanut butter. How many jars of creamy peanut butter
olya-2409 [2.1K]
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Eugene walked all the way to school at 3 mph then realized she forgot her math book (how could she?!), so she ran back at 7 mph.
Fynjy0 [20]

\text{Answer: }1\frac{23}{40}\ miles\text{ far she live from school.}

Explanation:

Since we have given that

Speed at which Eugene walked all the way to school = 3 mph

After realizing that she forgot her math book, she ran back

Speed at which Eugene walked back to her house = 7 mph

Let the distance between her house and her school be x

According to question,

\frac{x}{3}+\frac{x}{7}=\frac{45}{60}\\\\\frac{7x+3x}{21}=\frac{3}{4}\\\\\frac{10x}{21}=\frac{3}{4}\\\\x=\frac{3\times 63}{4\times 10}=\frac{63}{40}=1\frac{23}{40}\ miles.

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1\frac{23}{40}\ miles\text{ far she live from school.}

8 0
3 years ago
Solve for n in the proportion. If possible, first simplify the known fraction.
artcher [175]
N/17 = 70/50

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4 0
4 years ago
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Helen [10]

Answer:

1. SSS

2. SAS

3. SAS

4. SSS

5. SAS

6. SAS

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1) Side FY ≅ Side CW  Given

Side FP ≅ Side CM     Given

Side YP ≅ Side MW    Given

∴ΔMCW ≅ ΔFPY by the Side-Side-Side (SSS) rule of congruency

2) ∠CBD ≅ ∠BCA given that both are alternate interior angles

Side EB ≅ Side EC and Side DB ≅ Side CA Given

ΔBED ≅ ΔAEC by Side-Angle-Side (SAS) rule of congruency

3. ∠SVU ≅ ∠SVT   Given

Side SV ≅ Side SV  by reflexive property

Side VT ≅ Side VU   Given

∴ ΔVSU ≅ ΔVST by Side-Angle-Side (SAS) rule of congruency

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Side MQ ≅ Side NP     Given

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5. Indirect proof

Side GL ≅ Side HL  Given

Side GJ ≅ Side HK     Given

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Similarly

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Side XZ ≅ Side XZ  by reflexive property

Side ZW ≅ Side ZY   Given

∴ ΔXYZ ≅ ΔXWZ by Side-Angle-Side (SAS) rule of congruency.

3 0
3 years ago
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