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luda_lava [24]
3 years ago
8

An organization will give a prize to a local artist. The artist will be randomly chosen from among 7 painters, 4 sculptors, and

5 photographers. What is the probability that the artist choosen will be a painter or a photographer?
Mathematics
1 answer:
Usimov [2.4K]3 years ago
8 0
The probability would be 12/16 or 75%.
Hope this helps!
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Solve For x Help pleaassee
Mkey [24]

Answer:

x=4

Step-by-step explanation:

C+E=180

14x-8+132=180

14x=180-132+8

14x=56

x=4

6 0
3 years ago
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What is the reciprocal of -6
dem82 [27]
-.1666666666 is the reciprocal of -6
8 0
4 years ago
The measure of A is 75°, and the measure of B is 105°. What is the relationship of angles A and B?
Leni [432]

Answer:

D supplementary angles

Step-by-step explanation:

7 0
3 years ago
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The dimensions of a rectangle are √50a^3b^2 and √200a^3. What is the students error?
bearhunter [10]

Answer:

The student incorrectly simplified 30ab\sqrt{2a}+20a\sqrt{2a} .

Thus, option D is correct.

<u></u>

Step-by-step explanation:

The formula to determine the Perimeter of a rectangle of width w and length l is expressed as:

P = 2l + 2w

In other words, the perimeter can be determined by multiplying the length and width by 2 and adding the result.

In our case, the dimensions of a rectangle are \sqrt{50a^3b^2}  and  \sqrt{200a^3}\:\:.

Here is the student's solution:

2\sqrt{50a^3b^2}+2\sqrt{200a^3}=2\cdot 5ab\sqrt{2a}+2\cdot 10a\sqrt{2a}

                                 =10ab\sqrt{2a}+20a\sqrt{2a}

                                 =30ab\sqrt{2a}          

The student made an error in calculating 30ab\sqrt{2a}+20a\sqrt{2a} , because 30ab\sqrt{2a}+20a\sqrt{2a} are not like terms.

Hence, 30ab\sqrt{2a}+20a\sqrt{2a} can not be simplified to 30ab\sqrt{2a}

Therefore, the student incorrectly simplified 30ab\sqrt{2a}+20a\sqrt{2a} .

Thus, option D is correct.

<u></u>

<u></u>

<u>Here is the correct Solution:</u>

2\sqrt{50a^3b^2}+2\sqrt{200a^3}=2\cdot 5ab\sqrt{2a}+2\cdot 10a\sqrt{2a}

                                 =10ab\sqrt{2a}+20a\sqrt{2a}

7 0
3 years ago
Read 2 more answers
Prove that triangle ABC is Isosceles, given the following points.
Umnica [9.8K]

Answer:

See below

Step-by-step explanation:

<u>Given points:</u>

  • A (3, -1) , B (9, 2) , C (6, -4)

First, plot the points on the coordinate plane (see attached)

<u>We see that AB and BC look the same. Let's find their length:</u>

  • AB = \sqrt{(9-3)^2+(2-(-1))^2} = \sqrt{6^2+3^2} = \sqrt{45} = 3\sqrt{5}
  • BC = \sqrt{(6-9)^2 + (-4-2)^2} = \sqrt{3^2 + (-6)^2} = \sqrt{45} = 3\sqrt{5}

We showed that AB = BC = 3√5, so the triangle has two sided of the same length, therefore is isosceles.

6 0
3 years ago
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