Simplify \frac{5}{3}x35x to \frac{5x}{3}35x
x-\frac{5x}{3}<3x−35x<3
2
Simplify x-\frac{5x}{3}x−35x to -\frac{2x}{3}−32x
-\frac{2x}{3}<3−32x<3
3
Multiply both sides by 33
-2x<3\times 3−2x<3×3
4
Simplify 3\times 33×3 to 99
-2x<9−2x<9
5
Divide both sides by -2−2
x>-\frac{9}{2}x>−29
Answer:
78
Step-by-step explanation:
The IQR is quartile 3 - quartile 1. First, we need to find the mean of the dataset, which is 50 -- the fifth number. Then, the median of the dataset on the left of the fifth number is the first quartile, and the median of the dataset on the right is the third. We get Q1 to then be halfway between 30 and 50, or 40, and Q3 to be halfway between 56 and n, so Q3 = (56+n)/2. Since we need Q3-Q1=27, or (56+n)/2-40=27, we have (56+n)/2=67 and 56+n=134, so n = 134-56=78
D
Remember starts at zero slope is up 4 right 1
Y= 4/1x+0
Y=4x
-$67 because that is a greater change in amount than the other. (It also has a greater absolute value)
