The answer is 10^4 x 4^5.
You just have to subtract the powers for the term with 4 as it’s base.
Answer:
208.8 mi
Step-by-step explanation:
Form a triangle with the centre of the Earth (C) at one point, the horizon (H) as a second point, and the top of Mt. Everest (O) as the third (see diagram).
Let
r = Earth’s radius
h = height of Mt Everest
d = distance to horizon
∆CHO is a right triangle.
d² + r² = (r+h)²
d² + 3959² = (3959+5.5)²
d² + 15 673 681 = 3964.5²
d² + 15 673 681 = 15 717 260 Subtract 15 673 681 from each side
d² = 43 579 Take the square root of each side
d = 208.8 mi
The distance from the top of Mt Everest to the horizon is 208.8 mi.
(3n-2) x (4n+1) =0
All you need to do is to find what value of n makes each factor equal 0.
First Term:
3n-2 = 0
3n = 2
n = 2/3
Second Term:
4n+1 = 0
4n = -1
n = -1/4
n ={2/3, -1/4}
The answer is the number that 'x' must be in order for
that equation to be a true statement. Here's one way
to find out what the number is:
x + 36 = 4x
Subtract 'x' from each side: 36 = 3x
Divide each side by 3 : 12 = x
6
The 6 is the constant because it is never going to change
f(x), and others that contain x will change based on the value x
Since 6 doesn’t have the c with it it will be constant