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jekas [21]
3 years ago
8

5/8 - 5/12 ( 3 - 1/4 ) + 2/3 =

Mathematics
2 answers:
morpeh [17]3 years ago
4 0
<span>the answer is </span><span>0.145833333</span>
Alja [10]3 years ago
4 0
5/8 - 5/12 (3 - 1/4) + 2/3 =
5/8 - 5/12 (12/4 - 1/4) + 2/3 =
5/8 - 5/12 (11/4) + 2/3 =
5/8 - 55/48 + 2/3 =
30/48 - 55/48 + 32/48 =
7/48

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Billy has a savings account that has $1225
katrin2010 [14]

Answer:

1100 and 300

Step-by-step explanation:

4 0
3 years ago
Please help!
aleksklad [387]

Answer:

4 liters of 5% solution and 16 liters of 17.5% solution we need.

Step-by-step explanation:

Let us assume that x liters of 5% solution and y liters of 17.5% solution are taken.

So, x + y = 20 ........ (1)

As the final solution is of 15%, so we can write

\frac{\frac{5x}{100}+ \frac{17.5y}{100}}{x + y} = \frac{15}{100}

⇒ 5x + 17.5y = 300 ......... (2)

Now, solving equations (1) and (2)  we get,  

17.5y - 5y = 200

⇒ 12.5y = 200

⇒ y = 16 liters

Hence, x = 20 - y = 4 liters.

Therefore, 4 liters of 5% solution and 16 liters of 17.5% solution we need. (Answer)

4 0
4 years ago
Read 2 more answers
CAN SOMEONE PLEASE HELP ME WITH THIS​
kogti [31]

Answer:

The base has length 64 m.

Step-by-step explanation:

The area of a triangle = 1/2 * base * height so we have the equation:

256 = 1/2 * b * 8

4b = 256

b = 256/4 = 64 m.

7 0
3 years ago
What should be subtracted from thrice the rational number -8/3 to get 5/2?​
mezya [45]

Answer:

Sry don't know it lol. Stop answering my questions if you don't know it I want people that know the answer

7 0
3 years ago
Which expression is equivalent to (x^1/4y^16)^1/2 ?
jekas [21]

expression is equivalent to  (x^{\frac{1}{4}} y^{16})^{\frac{1}{2}}

We apply exponential property

Multiply the outside exponent 1/2 with exponents inside the parenthesis

(x^{\frac{1}{4}} y^{16})^{\frac{1}{2}}

(x^{\frac{1}{4}*\frac{1}{2}} y^{16*\frac{1}{2}})

1/4 times 1/2 is 1/8  

16 times 1/2 is 8

so expression becomes

(x^{\frac{1}{8}} y^{8})

So the answer is

(x^{\frac{1}{8}} y^{8})


3 0
3 years ago
Read 2 more answers
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