Central angle is 130
Semi circle is BED and BCD
Major arc is CEB
Measure BAC is 130
BEC is 230
Answer:
3/8 cups
Step-by-step explanation:
divide 3/4 by two
Answer:
Θ = 46°
Step-by-step explanation:
the angle between a tangent and a radius at the point of contact is 90° , so
∠ ABO = 90°
since OB = OD ( radii of circle ) then Δ BOD is isosceles and
∠ OBD = ∠ ODB = 22°
the exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.
∠ AOB is an exterior angle of the triangle , then
∠ AOB = 22° + 22° = 44°
the sum of the 3 angles in Δ AOB = 180° , then
Θ + 44° + 90° = 180°
Θ + 134° = 180° ( subtract 134° from both sides )
Θ = 46°
Answer:
k + 1
v(s) = -------------
S
Step-by-step explanation:
Solve the equation S=k/v(s)+1/v(s) for v(s).
To do this, combine the two terms on the right side, which is easily possible becuse they have the same denominator: v(s):
k + 1
S = ------------
v(s)
Now interchange S and v(s), obtaining:
k + 1
v(s) = -------------
S
