3 years ago

If the slope of a wheelchair ramp is 1/12 then what is the angle of inclination to the nearest tenth of a degree?

Mathematics

1 answer:

Orlov [11]3 years ago

8 0

Answer:

4.8 degrees to the nearest tenth.

Step-by-step explanation:

The slope = rise / run = opposite side / adjacent side.

So the angle of inclination is the angle whose tangent is 1/12.

To the nearest tenth of a degree it is 4.8 degrees.

You might be interested in

How many solutions does this equation have? <br><br><br> 7a+5(a+3) = 8a+4(a+2)

nikitadnepr [17]

Answer:

There is no solution

Step-by-step explanation:

4 0

3 years ago

4x + 2(2x – 5) – (3 – 5x).

bonufazy [111]

Answer:

=13x−13

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

If a sequence c1,c2,c3,...has limit K then the sequence ec1,ec2,ec3,...has limit e^K. Use this fact together with l'Hopital's ru

aleksandrvk [35]

Answer:

Step-by-step explanation:

If a sequence c1,c2,c3,...has limit K then the sequence ec1,ec2,ec3,...has limit e^K. Use this fact together with l'Hopital's rule to compute the limit of the sequence given by

bn=(n)^(5.6/n).

$L = \lim_{n \to \infty} b_n \\\\\\L= \lim_{n \to \infty} n^{\frac{5.6}{n} }$

Log on both sides

$In (L) = \lim_{n \to \infty} In (n)^{\frac{5.6}{n} }\\\\= \lim_{n \to \infty} \frac{5.6}{n} In(n)$

$=5.6 \lim_{n \to \infty} \frac{d}{dn} In(n)/\frac{d}{dn} (n)\\\\=5.6 \lim_{n \to \infty} \frac{1}{n} /1 \\\\=5.6 \lim_{n \to \infty} \frac{1}{n} \\\\=5.6 \times 0\\\\In(L) =0\\\\L=e^0\\\\L=1$