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ladessa [460]
3 years ago
5

What is a break along regular planes called in mineral identification?

Mathematics
1 answer:
Anestetic [448]3 years ago
3 0
Cleavage: 2-dimensional surfaces are known as cleavage planes.
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Based on this data what is reasonable estimate of the probability that it is sunny tomorrow
Romashka-Z-Leto [24]

No data here.................

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2 years ago
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the distance from the park to the grocery store is 0.9 mile. Ezra runs 8 tenths of that distance and walks the rest of the way.
Sholpan [36]

The distance from the park to the grocery store is 0.9 mile. Ezra runs 8 tenths of that distance and walks the rest of the way. The distance ezra runs can be solve by multiplying 8/10 to the total distance.

X = 0.9(8/10)=0.72 mile

6 0
3 years ago
What are the zero(s) of the function f(x)=<img src="https://tex.z-dn.net/?f=%5Cfrac%7B4x%5E%7B2%7D-36x%20%7D%7Bx-9%7D" id="TexFo
Contact [7]

Answer:

D

Step-by-step explanation:

The function will be zero when the numerator is equal to 0. So, set the numerator equal to 0 and solve:

0 = 4 {x}^{2}  - 36x

I will use the quadratic formula:

\frac{ 36  +  \sqrt{ {36}^{2}  - 4(4)(0)} }{2(4)}  \\  \frac{  36 + 36}{8}  = 9

Therefore, x = 9 is a 0. Let's check with subtracted root now:

\frac{ 36   -    \sqrt{ {36}^{2}  - 4(4)(0)} }{2(4)}  \\  \frac{ 36  -  36}{8}  =  0

It appears 0 is also a root.

Therefore, the answer is D.

7 0
3 years ago
A spacecraft is traveling with a velocity of v0x = 5320 m/s along the +x direction. Two engines are turned on for a time of 739
OlgaM077 [116]

Answer:

The velocities after 739 s of firing of each engine would be 6642.81 m/s in the x direction and 5306.02 in the y direction

Step-by-step explanation:

  1. For a constant acceleration: v_{f}=v_{0}+at, where  v_{f} is the final velocity in a direction after the acceleration is applied, v_{0} is the initial velocity in that direction  before the acceleration is applied, a is the acceleration applied in such direction, and t is the amount of time during where that acceleration was applied.
  2. <em>Then for the x direction</em> it is known that the initial velocity is v_{0x} = 5320 m/s, the acceleration (the applied by the engine) in x direction is a_{x} 1.79 m/s2 and, the time during the acceleration was applied (the time during the engines were fired) of the  is 739 s. Then: v_{fx}=v_{0x}+a_{x}t=5320\frac{m}{s} +1.79\frac{m}{s^{2} }*739s=6642.81\frac{m}{s}
  3. In the same fashion, <em>for the y direction</em>, the initial velocity is  v_{0y} = 0 m/s, the acceleration in y direction is a_{y} 7.18 m/s2, and the time is the same that in the x direction, 739 s, then for the final velocity in the y direction: v_{fy}=v_{0y}+a_{y}t=0\frac{m}{s} +7.18\frac{m}{s^{2} }*739s=5306.02\frac{m}{s}
8 0
3 years ago
Write a formula for S in terms of r.
bulgar [2K]

Answer:

Step-by-step explanation:

S=θ/360*2πr

S=0.020943951r

6 0
3 years ago
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