Answer:
G(3, 1), H(2, 3)
Step-by-step explanation:
When D is the midpoint of EG, it means ...
D = (E + G)/2
or
G = 2D -E = 2(3,4) -(3,7) = (2·3-3, 2·4-7) = (3, 1)
Likewise, H is ...
H = 2D -F = 2(3,4) -(4,5) = (2·3-4, 2·4-5) = (2, 3)
According to my calculations the theoretical answer about to be given is number c
Answer:
Step-by-step explanation:
Given equation of ellipsoids,
The vector normal to the given equation of ellipsoid will be given by
Hence, the unit normal vector can be given by,
Hence, the unit vector normal to each point of the given ellipsoid surface is
6x^2+14x+4
First factor out all numerical factors (=2 in this case)
2(3x^2+7x+2)
look for m,n such that m*n=3*2, m+n=7 => m=6, n=1
2(3x^2+6x + 1x+2)
Factor 3x^2+6x into 3x(x+2)
2( 3x(x+2)+1(x+2) )
factor out common factor (x+2)
2(x+2)(3x+1)
=>
6x^2+14x+4=2(x+2)(3x+1)