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kherson [118]
3 years ago
10

The measure of the inscribed angle is equal to ___ the measure of its intercepted arc.

Mathematics
2 answers:
rjkz [21]3 years ago
7 0

Answer:

the measure of the inscribed angle is equal to <em><u>half</u></em>___ the measure of its intercepted arc.

slamgirl [31]3 years ago
5 0

Answer:

the measure of the inscribed angle is equal to the measure of its intercepted arc.

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Please help asap 20 points
Fudgin [204]
D would be the answer.
5 0
3 years ago
Can someone please take a look at the attachment and tell me what the answer is? Serious answers only please!
siniylev [52]
The solid line indicates that the line itself is included in the solutions.  That the shaded area is to the left, or under, the line means that y≤the line.

To find the equation of the line you first find the slope or m using any two points.

m=(y2-y1)/(x2-x1)  in this case you are given (2,-5) and (-2, 3) so

m=(3--5)/(-2-2)

m=8/-4

m=-2

So far for y≤mx+b we have:

y=-2x+b  using either point we can solve for b, I'll use (2,-5)

-5=-2(2)+b

-5=-4+b

-1=b

So the line is:

y=-2x-1  and since y≤ the line:

y≤-2x-1
5 0
3 years ago
A lot is 60 m by 38 m. A house 32 m by 9 m is built on the lot. How much area is left over?
OLEGan [10]

Answer:

1992

Step-by-step explanation:

60x38=2280

32x9=288

2280-288=1992

Hope it helps!

3 0
2 years ago
Bill drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took 7 hours. When Bill
RUDIKE [14]

Answer: 315 miles

Step-by-step explanation:

let onward speed = x mph, then distance = 7x

return speed = (x+18) mph, (same) distance = 5(x+18)

equating the two,

7x = 5(x+18)

2x = 90 ==> x = 45 mph

so distance = 7*45 = 315 miles

7 0
3 years ago
What is the solution to -x2 + 5x - 3
CaHeK987 [17]

The solution to the equation is x=\frac{5-\sqrt{13}}{2} and x=\frac{5+\sqrt{13}}{2}

Explanation:

Given that the equation is -x^2+5x-3=0

We need to determine the solution of the equation.

The solution of the equation can be determined using the quadratic formula.

The quadratic formula is given by

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Hence, from the equation, we have,

a=-1,\:b=5,\:c=-3

Substituting these values in the quadratic formula, we get,

x=\frac{-5\pm \sqrt{5^2-4\left(-1\right)\left(-3\right)}}{2\left(-1\right)}

Simplifying, we get,

x=\frac{-5\pm \sqrt{25-12}}{-2}

Simplifying the terms within the root, we get,

x=\frac{-5\pm \sqrt{13}}{-2}

Thus, the roots of the equation are x=\frac{-5+ \sqrt{13}}{-2} and x=\frac{-5- \sqrt{13}}{-2}

Taking out the negative sign, we get,

x=\frac{-(5- \sqrt{13})}{-2} and x=\frac{-(5+ \sqrt{13})}{-2}

Cancelling the negative sign, we get,

x=\frac{5-\sqrt{13}}{2} and x=\frac{5+\sqrt{13}}{2}

Thus, the solutions of the equation are x=\frac{5-\sqrt{13}}{2} and x=\frac{5+\sqrt{13}}{2}

7 0
3 years ago
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