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weqwewe [10]
2 years ago
5

Which statement is true about this data set? 3,1, 6, 4, 4, 4, 3, 2, 5, 3

Mathematics
2 answers:
Kobotan [32]2 years ago
7 0

Answer:

What statements?

Step-by-step explanation:

iVinArrow [24]2 years ago
3 0

Is there a list of statements for this question? I would love to help!

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2x to the power of 2 + x = ? When x=9
oee [108]

Answer:

Step-by-step explanation:

2x to the power of 2 + x = ? When x=9

(2x)^2 + x

= 4x^2 + x

When x = 9

= 4(9)^2 + 9

= 4(81) + 9

= 324 + 9

= 333

8 0
3 years ago
Read 2 more answers
MN is a diameter of a circle with centre ' O ' . If BD = CD , prove that ∠OAD = ∠OCD
Varvara68 [4.7K]

Answer:

\sf \: Proved \: \angle \: OAD  \:  =  \angle \: OCD

Step-by-step explanation:

<em>Given:</em>

Mn is diameter of circle having centre O

and BD = OD,

<em><u>To prove that:</u></em>

<u>\angle \: OAD  \:  =  \angle \: OCD</u>

<em>Solution:</em>

Join the points O and B and draw OB,

On joining the line,

in ∆OCD and ∆OBD,

OC =OB → (Radius of same circle)

BD =CD → (from given)

OD =OD → (Common side in both the triangles)

Hence ∆OCD and ∆OBD are congruent from SSS property.

so we can say that,

\angle \: OBD  \:  =  \angle \: OCD

Consider above prove as statement A

Corresponding angles of congruent traingle.

in ∆ OAB,

OA = OB (radius of same circle)

hence ∆OAB is an isosceles traingle.

We know that opposite angle of isosceles traingle are always equal. hence,

\angle \: OBD  \:  =  \angle \: OAB \\ \angle \: OAB  \:  =  \angle \: OAD (same \: angles) \\ \angle \: OBD  \:  =  \angle \: OAD

Consider above prove as statement B

From Statement A & B we can say that

\angle \: OAD  \:  =  \angle \: OCD

<em>Thanks for joining brainly community!</em>

5 0
2 years ago
Khan Academy btw
Irina-Kira [14]

Answer:

B and D

Step-by-step explanation:

\frac{2^{5} }{6^{5} } = (\frac{1}{3} )^{5}

\frac{2^{5} }{6^{5} } = 2^{5}*6^{-5}

3 0
2 years ago
The dog in the pet shop are fed at 8:30 a.m and 5:30 p.m
Feliz [49]
Your answer would be 9 hours 
4 0
2 years ago
Read 2 more answers
Consider the following system of equations.
Sidana [21]
Y = 6x - 6  therefore   y - 6x = -6
y - 6x = 5 
so:
-6 ≠ 5
There is no solution to this system.
==========================
\left \{ {{y=6x-6} \atop {y-6x=5}} \right.  \\  \left \{ {{6x-y=6} \atop {-6x+y=5 }} \right.  \\ 0 \neq 11
6 0
3 years ago
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