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algol13
3 years ago
10

The area of a rectangle with width x and length

Mathematics
1 answer:
umka21 [38]3 years ago
5 0
Hey there :)

We are given:
The width = x
The length = 6x → this means the length is 6 times the width
                                           ↑
The coefficient 6 means this

Therefore, the answer will be option B
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The formula of the volume of a pyramid is 1/3BH, where B represents the area of the base of the pyramid and H represents the hei
zysi [14]

Answer:

It depends on the relation between the heights  of both pyramids

Step-by-step explanation:

We know the volume of a pyramid of base b and height h is

V=\frac{1}{3}bh

If the volume of the pyramid A is 3 times the volume of the pyramid B, then

\frac{1}{3}b_ah_a=3*\frac{1}{3}b_bh_b=b_bh_b

Which means

b_ah_a=3*b_bh_b

If we knew both heights are the same, we could conclude that

b_a=3*b_b

In which case the base of the pyramid A would be greater than the other base

But if, for example, the height of the pyramid A is 3 times the height of the other height, then

3*b_a=3*b_b=>b_a=b_b

Both bases would be the same.

If we choose that  

h_a >3*h_b

it would mean

b_a

In which case the base of the pyramid A would be less than the other base

So the answer entirely depends on the relation between the heights of both pyramids

3 0
3 years ago
Write words to match the expression, 3 + (4 × 12)
konstantin123 [22]
Three added to the product of four and twelve

or

The product of four and twelve added by three
6 0
3 years ago
Read 2 more answers
Please help i’m stuck in this and don’t know what to do
Sergio039 [100]
4 unit rate is 124. 5 unit rate is 16 6 unit rate is 60
8 0
3 years ago
Given: 2x^2+3x-5, g(x)=x+9. Find: (fg)(3)
Svetradugi [14.3K]

Answer:

264

Step-by-step explanation:

f(x)=2x^2+3x-5

g(x)=x+9

(fg)(x)=f(x) \times g(x)

\implies (fg)(x)=(2x^2+3x-5)(x+9)

(fg)(3)=(2(3)^2+3(3)-5)(3+9)

\implies (fg)(3)=22 \times 12

\implies (fg)(3)=264

8 0
2 years ago
What is the surface area of the prism?
cestrela7 [59]

Step 1: Find the area of the bases (triangles)

A = 1/2 * base * height

A = 1/2 * 16 * 6

A = 48

48 + 48 = 96

Area of the triangles = 96 cm^2

Step 2: Find the area of the sides (rectangles)

A = base * height

A1 = 16 * 12

A1 = 192

A2 = 10 * 12

A2 = 120

120 + 120 = 240

240 + 192 = 432 cm^2

Step 2: Add the areas together

96 + 432

528 cm^2

Hope this helps!! :)

5 0
3 years ago
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