3 years ago

What 11/5 cubic feet = to?

1 answer:

3 0

Answer:

Step-by-step explanation:

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ivolga24 [154]

For any distribution, the sum of the probabilities of all possible outcomes must be 1. In this case, we have to have

$P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4)=1$

We're told that $p=P(X=1)=P(X=2)$ , and we're given other probabilities, so we have

$0.25+2p+0.10+0.05=1\implies2p=0.6\implies p=0.3$

The expected number of calls would be

$E[X]=\displaystyle\sum_xx\,P(X=x)$

$E[X]=0\,P(X=0)+1\,P(X=1)+\cdots+4\,P(X=4)$

$E[X]=1.4$

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