Solve for w.
2=2(lw+lh+wh)
Flip the equation.
2hl+2hw+2lw=2
Add -2hl to both sides.
2hl+2hw+2lw+−2hl=2+−2hl
2hw+2lw=−2hl+2
Factor out variable w.
w(2h+2l)=−2hl+2
Divide both sides by 2h+2l.
w(2h+2l) / 2h+2l=−2hl+2 / 2h+2l
w=−hl+1/h+l
Answer:
Step-by-step explanation:
Volumes of two spheres A and B = 648 cm³ and 1029 cm³
Things to remember:
1). Scale factor of two objects = [ and are the radii of two circles]
2). Area scale factor =
3). Volume scale factor =
Volume scale factor Or Volume ratio =
Therefore, scale factor =
≈ 6 : 7
Area scale factor Or area ratio =
=
≈ 36 : 49
Volume scale factor or Volume ratio =
=
≈ 216 : 343
The question is defective, or at least is trying to lead you down the primrose path.
The function is linear, so the rate of change is the same no matter what interval
(section) of it you're looking at.
The "rate of change" is just the slope of the function in the section. That's
(change in f(x) ) / (change in 'x') between the ends of the section.
<u>In Section A:</u>
Length of the section = (1 - 0) = 1
f(1) = 5
f(0) = 0
change in the value of the function = (5 - 0) = 5
Rate of change =
(change in the value of the function) / (size of the section) = 5/1 =<em> 5</em>
<u>In Section B:</u>
Length of the section = (3 - 2) = 1
f(3) = 15
f(2) = 10
change in the value of the function = (15 - 10) = 5
Rate of change =
(change in the value of the function) / (size of the section) = 5/1 = <em> 5
</em><u>Part A:</u>
The average rate of change of each section is 5.
<u>Part B:</u>
<span><span>The average rate of change of Section B is equal to
t</span>he average rate of change of Section A.
<u>Explanation:</u>
The average rates of change in every section are equal
because the function is linear, its graph is a straight line,
and the rate of change is just the slope of the graph.
</span>
Answer:904.78
Step-by-step explanation: