<h3><u>Correct Questions :- </u></h3>
Find the values of P for which the quadratic equation 4x²+px+3=0 , provided that roots are equal or discriminant is zero .
<h3><u>Solution</u>:- </h3>
Let us Consider a quadratic equation αx² + βx + c = 0, then nature of roots of quadratic equation depends upon Discriminant (D) of the quadratic equation.
For equal roots

So,

Here,
Now,







Thus, the values of P for which the quadratic equation 4x²+px+3=0 are-
4√3 and -4√3.
Answer:
x = 12
y = -29
Step-by-step explanation:
Our given equations: x + y = -17 and x - y = 41
Solve for x and substitute.
x = -17 - y
(-17 - y) - y = 41
-17 - 2y = 41
2y = -58
y = -29
Solve for x using y
x + (-29) = -17
x = 12
Answer:
ME
Step-by-step explanation:
ME BC IMA GOD!