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2 years ago

A survey shows that 7 out of 8 customers are satisfied with the food served at Big Joe BBQ.

1 answer:

7 0

You would do 176 divided by 8 which equals 22, 7/8 is satisfied and 1/8 is unsatisfied. So it would be 1 x 22 which is 22 unsatisfied customers.

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Which step is not necessary when solving this system of equations by graphing? 3x-y=4 x+y= -4

lions [1.4K]

Answer: The answer is C: determine the shaded area for each line.

Just took the test on Edg.

Step-by-step explanation:

3 0

2 years ago

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Calculating Rate of change

ivolga24 [154]

Answer/Step-by-step explanation:

We are given the following coordinates of two points on the line of the graph shown in the question as: A(2, 1) and B(4, 2)

Vertical change from point A = $y_2 - y_1 = 2 - 1 = 1$

Horizontal change from point A = $x_2 - x_1 = 4 - 2 = 2$

Rate of change = $\frac{y_2 - y_1}{x_2 - x_1} = \frac{1}{2} = 0.5$

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2 years ago

The length of one side of a regular pentagon is 18.3 cm. What is the perimeter of this pentagon?

Ket [755]

91.5 is the perimeter. It's just 5a.

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3 years ago

Identify the equations as parallel lines, perpendicular lines, or neither.

Alex

Answer:

B. Parallel

Step-by-step explanation:

Equation 1 simplified: y = 3x+7

Equation 2 simplified: y = -x/3-3

The slopes are completely different, ruling out the possibility of the lines being parallel.

But we also see the slopes of the equations are opposite and negative to each other. Making the lines perpendicular.

4 0

2 years ago

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Find a compact form for generating functions of the sequence 1, 8,27,... , k^3

pantera1 [17]

This sequence has generating function

$F(x)=\displaystyle\sum_{k\ge0}k^3x^k$

(if we include $k=0$ for a moment)

Recall that for $|x|$ , we have

$\displaystyle\frac1{1-x}=\sum_{k\ge0}x^k$

Take the derivative to get

$\displaystyle\frac1{(1-x)^2}=\sum_{k\ge0}kx^{k-1}=\frac1x\sum_{k\ge0}kx^k$

$\implies\dfrac x{(1-x)^2}=\displaystyle\sum_{k\ge0}kx^k$

Take the derivative again:

$\displaystyle\frac{(1-x)^2+2x(1-x)}{(1-x)^4}=\sum_{k\ge0}k^2x^{k-1}=\frac1x\sum_{k\ge0}k^2x^k$

$\implies\displaystyle\frac{x+x^2}{(1-x)^3}=\sum_{k\ge0}k^2x^k$

Take the derivative one more time:

$\displaystyle\frac{(1+2x)(1-x)^3+3(x+x^2)(1-x)^2}{(1-x)^6}=\sum_{k\ge0}k^3x^{k-1}=\frac1x\sum_{k\ge0}k^3x^k$

$\implies\displaystyle\frac{x+4x^3+x^3}{(1-x)^4}=\sum_{k\ge0}k^3x^k$

so we have

$\boxed{F(x)=\dfrac{x+4x^3+x^3}{(1-x)^4}}$

5 0

3 years ago