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Thepotemich [5.8K]
3 years ago
11

A two digit number is such that, the sum of its digit is 13.When the digits are interchange, the original number is increased by

9. Find the original number.​
Mathematics
1 answer:
wlad13 [49]3 years ago
4 0

Answer:

Concept: Mathematical Representation

  1. You have a two digit # __
  2. The sum of the two digit # = 13
  3. The original # increased by 9
  4. Hence we must find values that sum to 13. *Note they must be independently standing.
  5. 8+5, 9+6, 7+6 , 6+7 , and etc
  6. The value must also increase by 9
  7. So logically it would be any result that when switched that value would be 76-67= 9.
  8. So the value must be 67
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A popcorn company builds a machine to fill 1 kg bags of popcorn. They test the first hundred bags filled and find that the bags
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Answer:

Step-by-step explanation:

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two terms of an arithmetic sequence are a6= 40 and a20= -16. write and explicit rule for the nth term
Lana71 [14]

Answer:

Tn = 64-4n

Step-by-step explanation:

The nth term of an AP is expressed as:

Tn = a+(n-1)d

a is the common difference

n is the number of terms

d is the common difference

Given the 6th term a6 = 40

T6 = a+(6-1)d

T6 = a+5d

40 = a+5d ... (1)

Given the 20th term a20 = -16

T20 = a+(20-1)d

T20 = a+19d

-16 = a+19d... (2)

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Subtracting both equation

40-(-16) = 5d-19d

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d = -4

Substituting d = -4 into equation

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a = 20+40

a = 60

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Tn = a+(n-1)d

Tn = 60+(n-1)(-4)

Tn = 60+(-4n+4)

Tn = 60-4n+4

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7 0
3 years ago
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gladu [14]
IT'S B..............;)
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Read 2 more answers
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