A two digit number is such that, the sum of its digit is 13.When the digits are interchange, the original number is increased by
9. Find the original number.
1 answer:
Answer:
Concept: Mathematical Representation
- You have a two digit # __
- The sum of the two digit # = 13
- The original # increased by 9
- Hence we must find values that sum to 13. *Note they must be independently standing.
- 8+5, 9+6, 7+6 , 6+7 , and etc
- The value must also increase by 9
- So logically it would be any result that when switched that value would be 76-67= 9.
- So the value must be 67
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Answer:
(d-3)/2
Step-by-step explanation:
Difference is subtraction
(d-3)/2
Answer:
Step-by-step explanation:
× 
( multiply values on numerators/ denominators together )
= 
=
20% =20/100=2/10
20% of 400 =(2/10)*400 =80
1/4 of 360= (1/4)*360 =90
90>80, so 1/4 of 360 is bigger than 20% of 400
Answer:
10 times greater
Step-by-step explanation:
Because value of 5 in 503 is 5*100
Then the value of 5 in 53 is 5*10
So then value of 5 in 503 is 10 times greater than the value of 5 in 53
I hope this helps
Answer:
b = 3.1
Step-by-step explanation:
Since the length of one of the longer sides, a, has been given to be 6.3, plug it into the equation.
2(6.3) + b = 15.7
12.6 + b = 15.7
b = 15.7 - 12.6
