Answer: maximum height of the football = 176 feet
Step-by-step explanation:
We want to determine the maximum height of the football from the ground. From the function given,
h(t) = -16t^2+96t +32, it is a quadratic function. Plotting graph if h will result to a parabolic shape. The maximum height of the football = the vertex of the parabola. This vertex is located at time, t
t = -b/2a
b = 96 and a= -16
t = -b/2a = -96/2×-16= 3
Substituting t = 3 into the function if h
h(t) = -16×3^2+96×3 +32
=-16×9 + 96×3 +32
= -144+ 288+32
=176 feet
Answer:
A choice
Step-by-step explanation:
sec is defined as 1/cos.
cos is again defined as adjacent to hypotenuse.
We know that adjacent is x and hypotenuse is r.
Therefore:- cos is x/r
Now sec is 1/cos = 1/(x/r)
1 ÷ x/r is 1•r/x
Thus:-
sec is r/x
Answer:
t = (v-u)/y
Step-by-step explanation:
yt = v - u
t = (v-u)/y
2) Larger triangle is twice as large as the smaller one so x is 16
3) 16/12.8= 1.25 (This is the scale factor)
for y: 10/1.25=8
for x: 30/1.25=16
4) 8/6.4=1.25 (Scale factor)
for y: 14/1.25=11.2
for x: 15/1.25= 12
5) 22.5/9= 2.5 (scale factor)
for x: 12x2.5=30
for y: 35/2.5= 14
6) No because the scale factor is 2 but 14/8 does not equal to 2
Cubic centimeters, because cubic is used for volume. Hope this helps! Happy Studying!
