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3 years ago

13

A town's speed limit is 25 miles per hour. Manny received a citation for driving too fast. If Manny was driving 36 percent over

the speed limit when he received his citation, how fast was he driving?
A: 61 mph

B:31 mph

C: 42 mph

D: 34 mph

10 points

2 answers:

LuckyWell [14K]3 years ago

8 0

Answer:

34 mph

Step-by-step explanation:

Firstly we will take 36% of 25 by following formula 36/100 ×25
We will get the answer 9
Now add this answer in 25 which is equal to 34

andrezito [222]3 years ago

5 0

Answer:

D. 34 mph

Step-by-step explanation:

I think

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Read 2 more answers

Determine the resultant of the given vectors by component method. E = 23 km , 11 degrees N of E N = 25 km, 24 degrees E of N G =

boyakko [2]

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The resultant of the given vectors by component method is $\vec U = -8.222\,\hat{i}+35.664\,\hat{j}\,\,\,[km]$ .

Step-by-step explanation:

First we define each vector by applying using rectangular form:

1) $\|\vec E\| = 23\,km$ , 11º north of east.

$\vec E = 23\,km\cdot (\cos 11^{\circ}\,\hat{i}+\sin 11^{\circ}\,\hat{j})$ (Eq. 1)

2) $\|\vec N\| = 25\,km$ , 24º east of north.

$\vec N = 25\,km\cdot (\sin 24^{\circ}\,\hat{i}+\cos 24^{\circ}\,\hat{j})$ (Eq. 2)

3) $\|\vec G\| = 19\,km$ , 18º south of west.

$\vec G = 19\,km\cdot (-\cos 18^{\circ}\,\hat{i}-\sin 18^{\circ}\,\hat{j})$ (Eq. 3)

4) $\|\vec R\| = 27\,km$ , 58º west of north.

$\vec R = 27\,km\cdot (-\sin 58^{\circ}\,\hat{i}+\cos 58^{\circ}\,\hat{j})$ (Eq. 4)

The resultant of given vectors is determined by vector sum, that is:

$\vec U = \vec E + \vec N + \vec G + \vec R$ (Eq. 5)

$\vec U = 23\,km\cdot (\cos 11^{\circ}\,\hat{i}+\sin 11^{\circ}\,\hat{j})+25\,km \cdot (\sin 24^{\circ}\,\hat{i}+\cos 24^{\circ}\,\hat{j})+19\,km\cdot (-\cos 18^{\circ}\,\hat{i}-\sin 18^{\circ}\,\hat{j})+27\,km\cdot (-\sin 58^{\circ}\,\hat{i}+\cos 58^{\circ}\,\hat{j})$

$\vec U = (23\,km\cdot \cos 11^{\circ}+25\,km\cdot \sin 24^{\circ}-19\,km\cdot \cos 18^{\circ}-27\,km\cdot \sin 58^{\circ})\,\hat{i}+(23\,km\cdot \sin 11^{\circ}+25\,km\cdot \cos 24^{\circ}-19\,km\cdot \sin 18^{\circ}+27\,km\cdot \cos 58^{\circ})\,\hat{j}$

$\vec U = -8.222\,\hat{i}+35.664\,\hat{j}\,\,\,[km]$

The resultant of the given vectors by component method is $\vec U = -8.222\,\hat{i}+35.664\,\hat{j}\,\,\,[km]$ .

7 0

3 years ago