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2 years ago

If the value of a is 8 in f(x)=ax^2, what does the graph look like?

Mathematics

1 answer:

viktelen [127]2 years ago

6 0

Step-by-step explanation:

the answer is in the image above

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The highest elevation in a small country occurs on a mountain 1,232 meter above sea level, while the lowest elevation in the sam

Arte-miy333 [17]

Answer: 1,259 meters.

Step-by-step explanation:

GIven: The highest elevation in a small country occurs on a mountain above sea level = 1,232 meter

The lowest elevation in the same country occurs below sea level = -27 meters

The difference in elevation between the highest and lowest points = Highest - lowest

= 1232 - (-27) meters

= 1232+27 meters [ (-)(-)=(+) ]

= 1259 meters

Hence, the difference in elevation between the highest and lowest points = 1,259 meters.

6 0

2 years ago

If log 5 = p and log 2=q then log 200 can be written in terms of p and q as?

Andrei [34K]

<h3>Answer: 2p + 3q</h3>

Work Shown:

log(200) = log(2^3*5^2)

log(200) = log(2^3) + log(5^2)

log(200) = 3*log(2) + 2*log(5)

log(200) = 3*q + 2*p

log(200) = 2p + 3q

The log rules I used were

log(A*B) = log(A)+log(B)

log(A^B) = B*log(A)

8 0

2 years ago

Vector u has a magnitude of 7 units and a direction angle of 330°. Vector v has magnitude of 8 units and a direction angle of 30

Dafna11 [192]

Keeping in mind that x = rcos(θ) and y = rsin(θ).

we know the magnitude "r" of U and V, as well as their angle θ, so let's get them in standard position form.

$\bf u=
\begin{cases}
x=7cos(330^o)\\
\qquad 7\cdot \frac{\sqrt{3}}{2}\\
\qquad \frac{7\sqrt{3}}{2}\\
y=7sin(330^o)\\
\qquad 7\cdot -\frac{1}{2}\\
\qquad -\frac{7}{2}
\end{cases}\qquad \qquad v=
\begin{cases}
x=8cos(30^o)\\
\qquad 8\cdot \frac{\sqrt{3}}{2}\\
\qquad \frac{8\sqrt{3}}{2}\\
y=8sin(30^o)\\
\qquad 8\cdot \frac{1}{2}\\
\qquad 4
\end{cases}$

$\bf u+v\implies \left( \frac{7\sqrt{3}}{2},-\frac{7}{2} \right)+\left( \frac{8\sqrt{3}}{2},4 \right)\implies \left( \frac{7\sqrt{3}}{2}+\frac{8\sqrt{3}}{2}~~,~~ -\frac{7}{2}+4\right)
\\\\\\
\left(\stackrel{a}{\frac{15\sqrt{3}}{2}}~~,~~ \stackrel{b}{\frac{1}{2}}\right)\\\\
-------------------------------$

$\bf tan(\theta )=\cfrac{b}{a}\implies tan(\theta )=\cfrac{\frac{1}{2}}{\frac{15\sqrt{3}}{2}}\implies tan(\theta )=\cfrac{1}{15\sqrt{3}}
\\\\\\
\measuredangle \theta =tan^{-1}\left( \cfrac{1}{15\sqrt{3}} \right)\implies \measuredangle \theta \approx 2.20422750397203^o$

8 0

2 years ago

How much would $400 invested at 9% interest compounded continuously be worth after 3 years? Round your answer to the nearest cen

adell [148]

<span>In 3 years, you will have $523.97
</span><span>continuously = daily</span>

3 0

3 years ago

Read 2 more answers

What percent of 12.4 is 12.4

NARA [144]

To find a percentage divide the first number by the second.

$\frac{12.4}{12.4}$ = $\frac{1}{1}$ =1.00

Now that you have your number, move the decimal point over 2 to the right and add your percentage sign.

100.00%

Your answer is 100%

3 0

3 years ago

Read 2 more answers