All categories

2 years ago

If the value of a is 8 in f(x)=ax^2, what does the graph look like?

Mathematics

1 answer:

viktelen [127]2 years ago

6 0

Step-by-step explanation:

the answer is in the image above

You might be interested in

Please help it is due in an hour

Soloha48 [4]

I now answer but u was a day late sorry

Step-by-step explanation:

8 0

2 years ago

A car tire is spinning a complete revolution every 0.60 seconds. The valve stem is 2 inches above ground at its lowest point and

finlep [7]

Answer:

Step-by-step explanation:

What is the amplitude, ||, of the height and co-height functions for this car tire

|| = 6

Let () represent the co-height function after rotation by radians, and let () represent the height function after rotation by radians. Write functions for the co-height and for the height in terms of .

() = ()

The co-height graphs are the same but translated 2 inches upward

so our function is:

() = () + 2 or

() = () + 2

5 0

3 years ago

Peter has four horses.Each one eats 4 pounds of oats,twice a day.How many pounds of oats does he need to feed his horses for 3 d

Kobotan [32]

4 pound of oats twice a day= 8 pounds of oats each day per horse. He has 4 horses so 4 horses times 8 pounds of oats is 32. You multiply 32 pounds times the three days he has to feed which is 96 pounds.

8 0

3 years ago

Read 2 more answers

What is the unit length of a'b'

ladessa [460]

5
is thr correct answer

8 0

3 years ago

Determine which equation is parallel to the line JK and which is perpendicular to like JK

sattari [20]

Answer:

If the equation of JK is y = mx + c, then y = mx + c' is the equation of the straight line parallel to above and $y = - \frac{1}{m}x + b$ will be perpendicular to that.

Step-by-step explanation:

Let us assume that the line JK has the equation in slope-intercept form as

y = mx + c ............. (1)

Therefore, the equation has slope = m

Now, any straight line having an equation with slope m will be parallel to line JK.

So, the equation of the straight line which is parallel to equation (1) will be

y = mx + c', where, c' is any real constant.

Now, let us assume that another straight line having equation

y = nx + a is perpendicular to the line JK i.e. equation (1).

Now, we know if two lines are perpendicular to each other then the product of their slopes will be - 1.

So, mn = - 1

⇒ $n = - \frac{1}{m}$

Therefore, the equation of a straight line which is perpendicular to equation (1) will be $y = - \frac{1}{m}x + b$ where b is any real constant. (Answer)

3 0

3 years ago

Read 2 more answers