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3 years ago

Find the area of a regular hexagon with a side length of 10 cm

Mathematics

2 answers:

Inessa [10]3 years ago

6 0

60 is my resultados of area

alexandr1967 [171]3 years ago

5 0

Answer

$54 \sqrt{3}$

Step-by-step explanation:

Each interior angle is 120°for an hexagon.... Bisecting each will give an angle of 60° and thus dividing the hexagon into 6 equilateral triangles as the Bisecting lines meet at the centre of the hexagon. So find area of each equilateral triangle and multiply by 6

Area=

$\frac{1}{2} b \times h \times 6 \\ = 3bh \\ = 3 \times 6 \times 3 \sqrt{3}$

$= 54 \sqrt{3 } cm ^{2}$

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2 years ago

In the diagram mz3= x+ 30 and mz4 =2x-80. What is the measure of angle 3?

Andreas93 [3]

Given:

Consider the below figure attached with this question.

$m\angle 3=(x+30)^\circ$ and $m\angle 4=(2x-80)^\circ$ .

To find:

The measure of angle 3.

Solution:

From the below figure it is clear that, angle 3 and angle 4 are vertically opposite angles.

We know that, vertically opposite angles are always equal. So,

$m\angle 3=m\angle 4$

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$x+30=2x-80$

$x-2x=-30-80$

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3 years ago

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3 years ago

Linear equation 4.5 + 1.5y=24 x-y=4

WARRIOR [948]

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2 years ago