Question

Find the area of a regular hexagon with a side length of 10 cm

Answer 1

60 is my resultados of area

Answer 2

Answer

$54 \sqrt{3}$

Step-by-step explanation:

Each interior angle is 120°for an hexagon.... Bisecting each will give an angle of 60° and thus dividing the hexagon into 6 equilateral triangles as the Bisecting lines meet at the centre of the hexagon. So find area of each equilateral triangle and multiply by 6

Area=

$\frac{1}{2} b \times h \times 6 \\ = 3bh \\ = 3 \times 6 \times 3 \sqrt{3}$

$= 54 \sqrt{3 } cm ^{2}$