Answer:
can you be more specific
Step-by-step explanation:
Answer:
Step-by-step explanation:
Use SOH CAH TOA to recall how the trig functions fit on a triangle
SOH: Sin(Ф)= Opp / Hyp
CAH: Cos(Ф)= Adj / Hyp
TOA: Tan(Ф) = Opp / Adj
7)
now decide which parts we know and what we want to slove for and pick the function that has those in it
we also know that small angle down at the point b/c we can use that the inside of trianle angles add to 180
180 = 75 + 90 + X
15° = X
where x is the angle at that sharp point on the triangle
I want to use that 15° angle in one of the above formulas as it's Opposite of that side we want to know, and also adjcent to that side we know , so i'll pick TOA since it's got all of those in it. Opp = x for this triangle
Tan(15) = Opp / 15
15* Tan(15) = Opp
4.0192 = Opp
so that's x
x = 4.0162 units , what ever they are
8)
the angle is 43° and we know the adjacent side and we want the Hypotenuse , now i'll pic CAH since it's got those pieces in it
Cos(43)= 31 / Hyp
some algebra just to switch Hyp out of the denominator
Hyp = 31 / Cos(43)
some tapping on my calculator
Hyp = 41.714
That's x for the second triangle
x = 41.71 units , what ever they are
:)
Answer:
12
Step-by-step explanation:
The difference of the two coordinates is ...
23 -(-10) = 33
The desired coordinate is 2/3 of that length from J, so is ...
J + (2/3)·33 = J +22 = -10 +22 = 12
The desired coordinate is 12.
7 and 1 for 6
and 4 and 4 make 8 right?
Answer:
a= <u>2</u><u>7</u>
6
Step-by-step explanation:
-6a + 4 = -23
or, -6a = -23 - 4
or, -6a = -27
or, a = <u>2</u><u>7</u>
6
