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3 years ago

Where is the point where the two lines meet? x + 5x y = -8x

Mathematics

2 answers:

Annette [7]3 years ago

7 0

The point where the lines intersect is (0, 0)

WINSTONCH [101]3 years ago

3 0

<h3>Answer:</h3>

$\large\boxed{(0,0)}$

<h3>Step-by-step explanation:</h3>

In this question, we're trying to find the point where to two lines meet.

Our equations are:

y = x + 5x
y = -8x

To find the point of intersection, we would first have to solve for x with both equations.

Solve:

$x + 5x \,\, -8x\\\\6x-8x\\\\-2x=0\\\\x= 0$

Now, we just plug in 0 to x to find the y.

$x + 5x \,\, -8x\\\\0+5(0)-8(0)\\\\0+0-0\\\\0$

When you put them into a coordinate, it would be (0,0).

The lines would intersect at (0,0), due to the fact that there is no beginning point for the equations.

<h3>I hope this helped you out.</h3><h3>Good luck on your academics.</h3><h3>Have a fantastic day!</h3>

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wariber [46]

A parabola is a mirror-symmetrical planar curve that is nearly U-shaped. The vertex of the parabola will lie at (-3,2).

<h3>What is the Equation of a parabola?</h3>

A parabola is a mirror-symmetrical planar curve that is nearly U-shaped.

y = a(x-h)² + k

where,

(h, k) are the coordinates of the vertex of the parabola in the form (x, y);

a defines how narrower is the parabola, and the "-" or "+" that the parabola will open up or down.

Comparing the given equation with the equation of a parabola, we will get,

y = a(x -h)² + k

y = -4(x+3)² + 2

Hence, the vertex of the parabola will lie at (-3,2).

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2 years ago

PLEASE PLEASE HELP ME, NO LINKS, I JUST NEED THIS DONE

lianna [129]

Answer:

Here is your answer

Step-by-step explanation:

B) 2x + 5 = 7

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C) 2x - y = 6

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D) 3y + 9 = 0

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3 years ago

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For the following right triangle, find the side length x. Round your answer to the nearest hundredth.

tia_tia [17]

<h3>Answer: 6.93</h3>

Work Shown:

Use the pythagorean theorem to find x

a^2 + b^2 = c^2

x^2 + 11^2 = 13^2

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x^2 = 169 - 121

x^2 = 48

x = sqrt(48)

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x = 6.93

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3 years ago

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PLEASE HELPPPPP!!!!!!!!! (show work if you can)

Kryger [21]

Answer:

$180x^4y^3z^2$

Step-by-step explanation:

Start by finding the LCM of the coefficients of each polynomial:

$LCM(12,18,30)=180$

Next, to find the least common multiple of each of the following terms, we need to take the absolute minimum we can of each term ( $x$ , $y$ , and $z$ ). The largest term of $x$ is $x^4$ in the first polynomial, so we'll take exactly that for our $x$ term in the LCM, absolutely nothing more. Similarly, the largest term of $y$ in any of the three polynomials is $y^3$ (also in the first polynomial) and the largest $z$ term in any of the three polynomials is $z^2$ in the second polynomial. Thus, the LCM of all our polynomials is: