Question

Can Someone write This in standard form? through: (3,5) Slope=5/3

Answer 1

The standard form of a line:

$Ax+By=C$

The point-slope form of a line:

$y-y_1=m(x-x_1)$

We have the point (3, 5) and the slope m = 5/3. Substitute:

$y-5=\dfrac{5}{3}(x-3)$

Convert it to the standard form:

$y-5=\dfrac{5}{3}(x-3)$        multioly both sides by 3

$3y-15=5(x-3)$        use distributive property

$3y-15=5x-15$      add 15 to both sides

$3y=5x$      subtract 3y from both sides

$5x-3y=0$