Point Form (1/2, 7) Equation Form x=1/2 y=7
Answer:
The fifth root is 2[cos(56°) + i sin(56°)]
Step-by-step explanation:
* To solve this problem we must revise De Moiver's rule
- In the complex number with polar form
∵ z = r(cosФ + i sinФ)
∴ z^n = r^n(cos(nФ) + i sin(nФ))
* In the problem
- The fifth root means z^(1/5)
- We can put 32 as a form a^n
∵ 32 = 2 × 2 × 2 × 2 × 2 = 2^5
∴ z = 2^5[cos(280°) + i sin(280°)]
* Lets find z^(1/5)
![*z^{\frac{1}{5}}=[2^{5}]^{\frac{1}{5} } (cos(\frac{1}{5})(280)+isin(\frac{1}{5})(280)](https://tex.z-dn.net/?f=%2Az%5E%7B%5Cfrac%7B1%7D%7B5%7D%7D%3D%5B2%5E%7B5%7D%5D%5E%7B%5Cfrac%7B1%7D%7B5%7D%20%7D%20%28cos%28%5Cfrac%7B1%7D%7B5%7D%29%28280%29%2Bisin%28%5Cfrac%7B1%7D%7B5%7D%29%28280%29)

∴ z^(1/5) = 2[cos(56) + i sin(56)]
* The fifth root of 32[cos(280°) + i sin(280°)] is 2[cos(56°) + i sin(56°)]
Answer:
22,203 ft^2
Step-by-step explanation:
The area of a triangle with angle ∅ and two sides a and b is;
Area A = 1/2 × absin∅ ......1
The park is in the shape of a triangle, with two sides and an angle given;
Given;
a = 190 ft
b = 235 ft
∅ = 84°
Substituting the values into equation 1;
Area of the park;
A = 1/2 × 190 × 235 × sin84°
A = 22,202.70131409 ft^2
A = 22,203 ft^2 (to the nearest whole number)
Area of the park is 22,203 ft^2
1.5 deep.
you subtract 2.25 of air space from the total depth 3.75
3.75-2.25=1.5